60+68=128
128/2=64
so the answer is 64
I hope this helped
Looking at the formula, each mol of P4O10 contains 4 mol of P, so
(58.5 mol P4O10) x (4 mol P/ 1 mol P4O10) = 234 mol
W = -P * delta V = - (1.00 atm)*(24.0 L - 1.00 L) = -23 L*atm (101.3 J/1 L*atm) = -233 J
It’s the second won the air layer one
Answer:
Refering to Chemistry,
The Group names are:
Group 6A: Chalcogens
Group 7A: Halogens
Group 8A: Noble/Inert Gasses
