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xeze [42]
2 years ago
10

During lab, you measured the heat of reaction by mixing solutions of FeCl3 and NaOH.

Chemistry
1 answer:
Kobotan [32]2 years ago
6 0

Explanation:

pls, refer to the above picture, i hope you will find it helpful.

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You have a red ballooe that has a volume of 20 liters, a pressure of 1.5 atmospheres and a temperature of 28 C. What is the volu
ki77a [65]

Explanation:

The given data is as follows.

 P_{1} = 1.5 atm,     V_{1} = 20 L,  T_{1} = (28 + 273) K = 301 K

   P_{2} = 5 atm,     V_{2} = ?,  T_{2} = (50 + 273) K = 323 K

Formula to calculate the volume will be as follows.

         \frac{P_{1} \times V_{1}}{T_{1}} = \frac{P_{2} \times V_{2}}{T_{2}}

Putting the given values into the above formula as follows.

        \frac{P_{1} \times V_{1}}{T_{1}} = \frac{P_{2} \times V_{2}}{T_{2}}  

        \frac{1.5 atm \times 20 L}{301 K} = \frac{5 atm \times V_{2}}{323 K}  

                 V_{2} = 0.64 L

Thus, we can conclude that the change in volume of the balloon will be 0.64 L.

6 0
3 years ago
The diagram below shows Earth, four different positions of the Moon, and the direction of incoming sunlight.
Allisa [31]

Answer:

im 99% sure its 2

Explanation:

7 0
3 years ago
What’s the density if the mass is 40.8g and the volume is 60mL?
luda_lava [24]

Answer:

We have the final answer as

<h2>0.68 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 40.8 g

volume = 60 mL

The density is

density =  \frac{40.8}{60}  \\

We have the final answer as

<h3>0.68 g/mL</h3>

Hope this helps you

8 0
3 years ago
What is the empirical formula of a compound that contains 75% Ag and 25% Cl by mass
lesya [120]

Answer:

The answer to your question is     AgCl

Explanation:

Data

Silver = Ag = 75%

Chlorine = Cl = 25%

1.- Convert percent numbers to grams

Silver = 75 g

Chlorine = 25 g

2.- Calculate the moles of each element

Mass number Ag = 108 g

Mass number Cl = 35.5 g

                            108 g of Ag ------------------  1 mol

                              75 g of Ag ------------------   x

                                x = (75 x 1) / 108

                                x = 75 / 108

                                x = 0.69 moles

                            35.5 g of Cl ------------------ 1 mol

                             25 g of Cl    -----------------   x

                                    x = (25 x 1) / 35.5

                                    x = 0.70 moles

3.- Divide by the lowest number of moles

Ag = 0.69/0.69 = 1

Cl = 0.70 / 0.69 = 1.02 ≈ 1

4.- Write the empirical formula

                                                 Ag₁ Cl₁  = AgCl

5 0
2 years ago
Calculate the area of an applied force of 300 N and a pressure of 35 Pa? (the answer needs to be accurate with 2 decimal places!
andreyandreev [35.5K]

Answer:

Explanation: 1Pa 1 N/m^2. p = F/A and A = F/p = 300N /35 Pa = 8.57 m^2

4 0
2 years ago
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