Answer:
1. the process of plants taking in sunlight and creating oxygen
2. outputs are oxygen
3. inputs are sunlight
Explanation:
Answer:
1.15 hours
Explanation:
If they are going 100 kilometers an hour, and they need to go 115 k, then do 115/100 which is 1.15 which is the time
Answer:
- <u><em>No, I would not consider a metal to be a plasma because plasma is just another state of matter, and the copper wire is in solid state.</em></u>
Explanation:
Metal is not a state of matter. Metals can be solid or liquid (molten) depending on their melting point and the temperature at which they are.
Plasma is a state of matter, similar to gas, but it is reached only at very high temperatures like in the Sun. The particles in plasma state are not neutral atoms or molecules but negatively charged ions and electrons.
The copper wire is yet a solid, thus it cannot be considered a plasma.
Metals can be in plasma state only if the temperature is too high, like the temperatures in the stars. In fact, the metals in the Sun and other hotter stars are in plasma state.
The equilibrium constant is 0.0022.
Explanation:
The values given in the problem is
ΔG° = 1.22 ×10⁵ J/mol
T = 2400 K.
R = 8.314 J mol⁻¹ K⁻¹
The Gibbs free energy should be minimum for a spontaneous reaction and equilibrium state of any reaction is spontaneous reaction. So on simplification, the thermodynamic properties of the equilibrium constant can be obtained as related to Gibbs free energy change at constant temperature.
The relation between Gibbs free energy change with equilibrium constant is ΔG° = -RT ln K
So, here K is the equilibrium constant. Now, substitute all the given values in the corresponding parameters of the above equation.
We get,
![1.22 * 10^{5} = - 8.314* 2400 * ln K](https://tex.z-dn.net/?f=1.22%20%2A%2010%5E%7B5%7D%20%3D%20-%208.314%2A%202400%20%2A%20ln%20K)
![\\ 1.22 * 10^{5} = -19953.6 * ln K](https://tex.z-dn.net/?f=%5C%5C%201.22%20%2A%2010%5E%7B5%7D%20%3D%20-19953.6%20%2A%20ln%20K)
![ln K = \frac{-1.22*10^{5} }{19953.6} =-6.114\\\\k =e^{-6.114}=0.0022](https://tex.z-dn.net/?f=ln%20K%20%3D%20%5Cfrac%7B-1.22%2A10%5E%7B5%7D%20%7D%7B19953.6%7D%20%3D-6.114%5C%5C%5C%5Ck%20%3De%5E%7B-6.114%7D%3D0.0022)
So, the equilibrium constant is 0.0022.