TheThe relative velocity of Deigo will be 27km/h .
<h3>What is relative Velocity? </h3>
The relative velocity is the velocity of an object with respect to another observer. It is the time rate of relative position of one object with respect to another object .
Vab = Va-Vb
Where a is object and b is observer .
We have given here the velocity of ball 20km/ h
and the another velocity is 7km/ h
Let us assume that Diego is also moving in the direction where ball is moving so the relative velocity will be
V = 20+7=27km/ h
When both observer and object is moving in same direction than there sum of velocity will be relative velocity ,if they are moving opposite than subtraction.
to learn more about Relative velocity click Here brainly.com/question/6070547
#SPJ4
Let's cut through the weeds and the trash
and get down to the real situation:
A stone is tossed straight up at 5.89 m/s .
Ignore air resistance.
Gravity slows down the speed of any rising object by 9.8 m/s every second.
So the stone (aka Billy-Bob-Joe) continues to rise for
(5.89 m/s / 9.8 m/s²) = 0.6 seconds.
At that timer, he has run out of upward gas. He is at the top
of his rise, he stops rising, and begins to fall.
His average speed on the way up is (1/2) (5.89 + 0) = 2.945 m/s .
Moving for 0.6 seconds at an average speed of 2.945 m/s,
he topped out at
(2.945 m/s) (0.6 s) = 1.767 meters above the trampoline.
With no other forces other than gravity acting on him, it takes him
the same time to come down from the peak as it took to rise to it.
(0.6 sec up) + (0.6 sec down) = 1.2 seconds until he hits rubber again.
Answer:
The position on the x axis is 0.32 m.
Explanation:
Given that,
Point charge = 27 nC
Charge = 6 nC
Distance = 1
We need to calculate the distance
Using formula of electric field
Put the value into the formula
Hence, The position on the x axis is 0.32 m.
Acceleration in m/s^2 = 2/10 = 0.2 m/s^2
