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Volgvan
3 years ago
6

mooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo

oooooooooom daaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaad
Engineering
2 answers:
Rina8888 [55]3 years ago
7 0

Answer:

mooooommmmmmmmmmdaddadddaddddddddaaaaaa

Explanation:

Oksana_A [137]3 years ago
6 0

Answer:

sssttteeeeeppppppbbrrrrooooo

Explanation:

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A digital automatic level is used to profile a road centerline. The backsight reading is 3.57 ft on BM #1, which has an elevatio
liubo4ka [24]

Answer:

209.55 ft

Explanation:

Given Data:

Benchmark:

Reduced Level or Elevation = 210.50

Height of Instrument = Reduced Level + Back sight Reading

Height of Instrument = 210.50 + 3.57 = 214.07 ft

Turning Point:

Back sight Reading = 2.91 ft

Fore Sight Reading = 4.52

Reduced Level or Elevation of Turning Point = Height of Instrument – fore sight Reading

Reduced Level or Elevation of Turning Point = 214.07 – 4.52 = 209.55 ft

Height of Instrument at Turning Point = Reduced Level + Back sight Reading

Height of Instrument at Turning Point = 209.55 + 2.91 = 212.46 ft

Download docx
4 0
3 years ago
In order to produce a certain semiconductor, a process called doping is performed in which phosphorus is diffused into germanium
Nimfa-mama [501]

Answer:

The diffusivity is given as 8.064\times 10^{-16} m^2/s

Explanation:

From the given data as in the attached question found via the search (because the values were not clear in this one)

D_o=2.0\times10^{-4}m^2/s\\Q_d=240.6 kJ/mol=2.406 \times 10^5 J/mol\\Gas Constant=R=8.314 J/mol K\\Temperature =830 C =830+273 =1103 K

So  the Diffusion coefficient is given as

D=D_oe^{\frac{-Q_d}{RT}}\\D=(2.0\times 10^{-4})e^{\frac{-2.406\times 10^5}{8.314\times 1103}}\\D=8.0640\times 10^{-16} m^2/s

So the diffusivity is given as 8.064\times 10^{-16} m^2/s

4 0
4 years ago
Do you think we would have a use for a technology that would mimic the flight of a hummingbird?
Margarita [4]

Answer:

I think we would.

Explanation:

Only if u invent it.

4 0
3 years ago
Read 2 more answers
The following figure shows the tensile stress-strain curve for a brass alloy.
Aleksandr-060686 [28]
(A)-The Theoretical Strength Is Higher Than The Experimental Strength.

7 0
3 years ago
Which level of acceleration should you use when accelerating on a short highway entry ramp?
ahrayia [7]

The lowest level of acceleration should be use when accelerating on a short highway entry ramp.

<h3>What is an acceleration?</h3>

This means the rate at which velocity changes with time in terms of both the speed and direction.

In a machine, this means rate at which a vehicle can increase its speed in terms of the time that it takes to reach a particular speed.

Because the short highway entry ramp need careful driving, then, the lowest level of acceleration should be use when accelerating on a short highway entry ramp.

Read more about acceleration

brainly.com/question/460763

#SPJ1

5 0
2 years ago
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