When the magnitude of the charge Q = I*T
when we have I current = 2.3
and T = 35 min * 60 = 2100 s
by substitution:
∴ Q = 2.3 * 2100
= 4830 C
according to this reaction equation:
Cu2+ + 2e- → Cu
we can see that 1 mol Cu2+ need 2 mol e- to produce Cu
mol of electron e- = Q / faraday's constant
= 4830 / 96485
= 0.05 mol
when 1 mol Cu2+ → 2 mol e-
?? ← 0.05 mol
∴ moles Cu2+ = 0.05 /2 = 0.025 mol
∴ mass Cu2+ = moles Cu2+ * molar mass Cu2+
= 0.025 * 64
= 1.6 g
Answer: Oxygen
Explanation:
As seen from the balanced equation:
2 moles of hydrogen combine with 1 mole of oxygen or 1 mole of hydrogen combine with 1/2 mole of oxygen.
According to Avogadro's law, equal volumes of gases contain equal number of molecules and hence equal number of moles.
Thus if x moles of both gases are present, x moles of hydrogen will combine with 
moles of oxygen and 
moles of oxygen will be left used and will be in excess.
When we have the balanced reaction equation is:
H2(g) + CO2(g) ↔ H2O(g) + CO (g)
a) first, to calculate ΔG° for the reaction:
we will use this formula:
ΔG° = -RT㏑Kp
when R is R- rydberg constant = 8.314J/mol.K
and T is the temperature in Kelvin = 2000 K
and Kp = 4.4
so, by substitution:
ΔG° = - 8.314 *2000 *㏑4.4
= - 24624 J/mol = - 24.6 KJ/mol
b) to calculate ΔG so, we will use this formula:
ΔG = ΔG° + RT㏑Qp
So we need first, to get Qp from the reaction equation:
when Qp = P products / P reactants
= PH2O*PCO / PH2 * PCO2
= (0.66 atm * 1.2 atm) / (0.25 * 0.78)
= 4.1
so by substitution:
ΔG = -24624 + 8.314*2000*㏑4.1
= -1162 J/mol = - 1.16 KJ/mol
Answer:
30 moles of water will produced.
Explanation:
Given data:
Number of moles of O₂ react = 15 mol
Number of moles of water formed = ?
Solution:
Chemical equation:
2H₂ + O₂ → 2H₂O
Now we will compare the moles of water with oxygen.
O₂ : H₂O
1 : 2
15 : 2×15 = 30 mol
30 moles of water will produced.
