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Elena L [17]
2 years ago
5

A 25 kg chair initially at rest on a horizontal floor requires a 365 N horizontal force to set it in motion. Once the chair is i

n motion, a 327 N horizontal force keeps it moving at a constant velocity.
a)Find the coefficient of static friction between the chair and the floor.
b)Find the coefficient of kinetic friction between the chair and the floor.
Physics
1 answer:
weqwewe [10]2 years ago
4 0

Answer:

Here's what you know, m=25 kg, Ff=365 N, g=9.8 m/s^2, use the formula Fg = mg, Fg =25*9.8, Fg =245 N, then use the formula Ff <= ตsFn, 365=245ตs, solve for ตs,  ตs=1.5.

Here's what ya know, m=25 kg, Ff=327 N, the normal force of gravity will be the same as in part A.  Now use the formula Ff = µkFn, 327=245 µk, solve for µk, µk=1.3.

Explanation:

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blondinia [14]

Answer:

1. Potential hazard

2. Mining opportunity

Explanation:

The two reason, why astronomers are so interested in the discovery of additional Earth-approaching asteroids:

1. Potential hazard: We have proof that the dinosaurs got extinct because of an asteroid/comet strike on Earth. Also we have seen the effects of the Tunguska event and Chelyabinsk tragedy. These are enough to show us that asteroids can be very dangerous and wipe out the life from Earth.

2. Mining Opportunity: We have discovered a lot of asteroids which contains a lot of metal and precious elements. There can be a possibility of mining such asteroids in the future and reducing the burden on Earth.

4 0
3 years ago
The shuttles main engine provides 154,360 kg of thrust for 8 minutes. If the shuttle accelerated at 29m/s/s, and fires for at le
Vinil7 [7]

Answer:

The answer to the question is

3340800 m far

Explanation:

To solve the question, we note that acceleration = 29 m/s²

Time of acceleration = 8 minutes

Then if the shuttle starts from rest, we have

S = u·t+0.5·a·t² where u = 0 m/s = initial velocity

S = distance traveled, m

a = acceleration of the motion, m/s²

t = time of travel

S = 0.5·a·t² = 0.5×29×(8×60)² = 3340800 m far

3 0
3 years ago
True/False: The points where the potential is the same (in three-dimensional space) lie on a surface.
nikdorinn [45]
1. True
2. False

Does that answer your question?
5 0
3 years ago
A 0.50 kilogram ball is held at a height of 20 meters. What is the kinetic energy of the ball when it reaches halfway after bein
mars1129 [50]
<span>(M G H)=(0.5 x 9.8 x 10) = 49 joules.</span>
4 0
3 years ago
On Mars, the acceleration due to gravity is 3.77 m / s 2 . 3.77 m/s2. How far would a 15 g 15 g rock fall from rest in 2.5 s 2.5
Zinaida [17]

Answer:

s = 11.78 m

Explanation:

given,

acceleration due to gravity, g = 3.77 m/s²

mass of the rock = 15 g

time = 2.5 s

distance traveled = ?

using equation of motion

s = ut +\dfrac{1}{2}at^2

initial speed = 0 m/s

s = \dfrac{1}{2}at^2

s = \dfrac{1}{2}\times 3.77 \times 2.5^2

s = 11.78 m

distance traveled by the rock is equal to 11.78 m.

7 0
3 years ago
Read 2 more answers
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