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2 years ago

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A 25 kg chair initially at rest on a horizontal floor requires a 365 N horizontal force to set it in motion. Once the chair is i

n motion, a 327 N horizontal force keeps it moving at a constant velocity.
a)Find the coefficient of static friction between the chair and the floor.
b)Find the coefficient of kinetic friction between the chair and the floor.

1 answer:

weqwewe [10]2 years ago

4 0

Answer:

Here's what you know, m=25 kg, Ff=365 N, g=9.8 m/s^2, use the formula Fg = mg, Fg =25*9.8, Fg =245 N, then use the formula Ff <= ตsFn, 365=245ตs, solve for ตs, ตs=1.5.

Here's what ya know, m=25 kg, Ff=327 N, the normal force of gravity will be the same as in part A. Now use the formula Ff = µkFn, 327=245 µk, solve for µk, µk=1.3.

Explanation:

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