(A) The oxygen atom becomes strongly negative.
Explanation:
When a very electronegative atom like oxygen bonds to an atom with a lower electronegativity, like lithium, the oxygen atom becomes strongly negative and the lithium becomes strongly positive.
The attraction between these oppositely charged ions results in the formation ionic bond.
- An ionic bond is an interatomic bond in which a highly electronegative atom is bonded to less electronegative one.
- The electronegative nature of the oxgyen allows is to gain the electrons lost by weakly electronegative lthium.
- Most metals have low electronegativity.
- They then both will form ions.
- The attraction between the oppositely charged ions results in an ionic/electrovalent bonding.
learn more:
Ionic bond brainly.com/question/6071838
#learnwithBrainly
Roughly 1609 meters in one mile
Answer:
The value of tangential acceleration 
40 
The value of radial acceleration 
Explanation:
Angular acceleration = 50 
Radius of the disk = 0.8 m
Angular velocity = 10 
We know that tangential acceleration is given by the formula 
Where r = radius of the disk
= angular acceleration
⇒ 0.8 × 50
⇒ 40
This is the value of tangential acceleration.
Radial acceleration is given by
Where V = velocity of the disk = r 
⇒ V = 0.8 × 10
⇒ V = 8 
Radial acceleration
This is the value of radial acceleration.
1. All the relevant resistors are in series, so the total (or equivalent) resistance is the sum of the resistances of the resistors: 20 Ω + 80 Ω + 50 Ω = 150 Ω [choice A].
2. The ammeter will read the current flowing through this circuit. We can find the ammeter reading using Ohm's law in terms of the electromotive force provided by the battery: I = ℰ/R = (30 V)(150 Ω) = 0.20 A [choice C].
3. The voltmeter will measure the potential drop across the 50 Ω resistor, i.e., the voltage at that resistor. We know from question 2 that the current flowing through the resistor is 0.20 A. So, from Ohm's law, V = IR = (0.20 A)(50 Ω) = 10. V, which will be the voltmeter reading [choice F].
4. Trick question? If the circuit becomes open, then no current will flow. Moreover, even if the voltmeter were kept as element of the circuit, voltmeters generally have a very high resistance (an ideal voltmeter has infinite resistance), so the current moving through the circuit will be negligible if not nil. In any case, the ammeter reading would be 0 A [choice B].
Answer:
<h2>
6.36 cm</h2>
Explanation:
Using the formula to first get the image distance
1/f = 1/u+1/v
f = focal length of the lens
u = object distance
v = image distance
Given f = 16.0 cm, u = 24.8 cm
1/v = 1/16 - 1/24.8
1/v = 0.0625-0.04032
1/v = 0.02218
v = 1/0.02218
v = 45.09 cm
To get the image height, we will us the magnification formula.
Mag = v/u = Hi/H
Hi = image height = ?
H = object height = 3.50 cm
45.09/24.8 = Hi/3.50
Hi = (45.09*3.50)/24.8
Hi = 6.36 cm
The image height is 6.36 cm
