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3 years ago

1. Name three obstacles that Mendeleev faced in his life?

Chemistry

1 answer:

Fittoniya [83]3 years ago

3 0

Answer:

was difficult to place isotopes of elements as they have the same chemical properties but different atomic masses. It was not possible to predict how many elements could be discovered between two heavy elements as the rise in atomic mass is not uniform.

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What is the half-life of Technetium-99 if a 200 gram sample decays to 50 grams in 639,000 years?

Elenna [48]

Answer:

The half-life of Th-232 is 1.4 ∙ 10¹⁰ years.

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3 years ago

Which condition would lower the salinity of ocean water? A. high rates of evaporation B. freezing of glaciers C. extremely hot w

Paraphin [41]

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4 years ago

Read 2 more answers

Consider the two gaseous equilibria: The values of the equilibrium constants K 1 and K 2 are related by

Sauron [17]

The question is missing parts. The complete question is as follows.

Consider the two gaseous equilibria involving SO2 and the corresponding equilibrium constants at 298K:

$SO_{2}_{(g)} + \frac{1}{2}O_{2}$ ⇔ $SO_{3}_{(g)}$ ; $K_{1}$

$2SO_{3}_{(g)}$ ⇔ $2SO_{2}_{(g)}+O_{2}_{(g)}; K_{2}$

The values of the equilibrium constants are related by:

a) $K_{1}$ = $K_{2}$

b) $K_{2} = K_{1}^{2}$

c) $K_{2} = \frac{1}{K_{1}^{2}}$

d) $K_{2}=\frac{1}{K_{1}}$

Answer: c) $K_{2} = \frac{1}{K_{1}^{2}}$

Explanation: <u>Equilibrium</u> <u>constant</u> is a value in which the rate of the reaction going towards the right is the same rate as the reaction going towards the left. It is represented by letter K and is calculated as:

$K=\frac{[products]^{n}}{[reagents]^{m}}$

The concentration of each product divided by the concentration of each reagent. The indices, m and n, represent the coefficient of each product and each reagent.

The equilibrium constants of each reaction are:

$SO_{2}_{(g)} + \frac{1}{2}O_{2}$ ⇔ $SO_{3}_{(g)}$

$K_{1}=\frac{[SO_{3}]}{[SO_{2}][O_{2}]^{1/2}}$

$2SO_{3}_{(g)}$ ⇔ $2SO_{2}_{(g)}+O_{2}_{(g)}$

$K_{2}=\frac{[SO_{2}]^{2}[O_{2}]}{[SO_{3}]^{2}}$

Now, analysing each constant, it is easy to see that $K_{1}$ is the inverse of $K_{2}$ .

If you doubled the first reaction, it will have the same coefficients of the second reaction. Since coefficients are "transformed" in power for the constant, the relationship is:

$K_{2}=\frac{1}{K_{1}^{2}}$

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3 years ago

For each reaction, write the chemical formulae of the oxidized reactants in the space provided. Write the chemical formulae of t

liberstina [14]

Explanation:

First Reaction;

Ca + ZnCl2 --> CaCl2 + Zn

Oxidized Reactant: Ca. There is increase in oxidation number from 0 to +2

Reduced Reactant: Zn. There is decrease in oxidation number form +2 to 0

Second Reaction:

FeI2 + Mg --> Fe + MgI2

Oxidized Reactant: Mg. There is increase in oxidation number from 0 to +2

Reduced Reactant: Fe. There is decrease in oxidation number form +2 to 0

Third Reaction;

Mg + 2AgNO3 --> Mg(NO3)2 + Ag

Oxidized Reactant: Mg. There is increase in oxidation number from 0 to +2

Reduced Reactant: Ag. There is decrease in oxidation number form +1 to 0

5 0

3 years ago

A solution is made by mixing 36. g of heptane (C_7H_16) and 16. g of chloroform (CHCl_3). Calculate the mole fraction of heptane

Diano4ka-milaya [45]

Answer:

Mole fraction of solute (heptane) → 0.73

Explanation:

Mole fraction = Moles of solute or solvent / Total moles

Let's calculate the moles of everything:

Moles of solute → Mass of solute / Molar mass

36 g / 100 g/mol = 0.36 moles

Moles of solvent → Mass of solvent / Molar mass

16 g / 119.35 g/mol = 0.134 moles

Total moles = 0.36 + 0.134 = 0.494 moles

Mole fraction of solute = 0.36 / 0.494 → 0.73

8 0

4 years ago

1. Name three obstacles that Mendeleev faced in his life? ​

1. Name three obstacles that Mendeleev faced in his life?