The question is incomplete. Complete question is attached below:
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Answer:
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL
We know that, M1V1 = M2V2
(HBr) (KOH)
Therefore, M2 = M1V1/V2
= 1.4 X 15.4/22.10
= 0.9756 M
Concentration of KOH is 0.9756 M.
The coefficient for the chemical formula 3CO2 is the 3.
Answer:
36.51%.
Explanation:
First find the percentage of iron in pure Fe2O3 using the atomic masses of the elements:
= (2 * 55.845) * 100 / (2*55.845+ 3*15.999)
= 69.94 %.
So the percentage of iron in the mixture
= 52.2 * 0.6994
= 36.51 (answer).
Answer:
Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation
Explanation:
Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation