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GarryVolchara [31]
2 years ago
7

Solve for x your answer must be simplified x-24>9

Mathematics
1 answer:
PtichkaEL [24]2 years ago
3 0

Answer:

x - 24 > 9

x > 33

Step-by-step explanation:

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Solve the logarithmic equation<br><br> log(3x)+log(2x)=3
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Hope this answer would be helpful.

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3 years ago
For the annual rate of change of +70%, find the corresponding growth or Decay Factor.
omeli [17]
Hello there!
1. Okay. So 70% is positive, so it is a corresponding growth. 70% is 0.7 in decimal form. C and D are both eliminated, because that's too large. When something grows by 70%, that is less than double. 0.7 is not right either, because that's more of a decay than a growth. The only answer that makes sense id 1.70, because you are going up, and adding 1 to decimal form brings you to the decimal that when multiplied will bring you to the total. The answer is B: 1.70.

2. So, -75% is negative, so it is a decay factor. A is eliminated, because it makes no sense and B is out, because that represents growth, not decay. You lose 75% of the amount overtime compounded, but you still have 25% that remains. To find that amount, you would subtract that amount from 1 to get the decay. 1 - 0.75 is 0.25. The decay factor is 0.25. The answer is D: 0.25.
4 0
3 years ago
5+x+(−2)=−85+x+(−2)=−8<br><br><br> x=?
sashaice [31]
5+x+(-2)=-85+x+(-2)=-8\\&#10;x-3=x-87=-8
x has no solution.
5 0
2 years ago
Hello can you please help me posted picture of question
astra-53 [7]
The answer is D because there is one of the 0 and one of the 9
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3 years ago
Read 2 more answers
Find the area each sector. Do Not round. Part 1. NO LINKS!!<br><br>​
sladkih [1.3K]

Answer:

\textsf{Area of a sector (angle in degrees)}=\dfrac{\theta}{360 \textdegree}\pi r^2

\textsf{Area of a sector (angle in radians)}=\dfrac12r^2\theta

17)  Given:

  • \theta = 240°
  • r = 16 ft

\textsf{Area of a sector}=\dfrac{240}{360}\pi \cdot 16^2=\dfrac{512}{3}\pi \textsf{ ft}^2

19)  Given:

  • \theta=\dfrac{3 \pi}{2}
  • r = 14 cm

\textsf{Area of a sector}=\dfrac12\cdot14^2 \cdot \dfrac{3\pi}{2}=147 \pi \textsf{ cm}^2

21)  Given:

  • \theta=\dfrac{ \pi}{2}
  • r = 10 mi

\textsf{Area of a sector}=\dfrac12\cdot10^2 \cdot \dfrac{\pi}{2}=25 \pi \textsf{ mi}^2

23)  Given:

  • \theta = 60°
  • r = 7 km

\textsf{Area of a sector}=\dfrac{60}{360}\pi \cdot 7^2=\dfrac{49}{6}\pi \textsf{ km}^2

3 0
2 years ago
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