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kondor19780726 [428]
3 years ago
15

Do any animals live in Antarctica?

Physics
2 answers:
Ratling [72]3 years ago
8 0

Answer:

Yes. Animals such as certain species of penguin and polar bear.

Explanation:

Do Penguins and polar bears live together?

It is always good to see penguin and polar bear together in commercials and movies. But, in reality, they are pole apart, being separated from warm waters of the equator; polar bears live in the Arctic, Northern Hemisphere whereas, penguins live in Southern Hemisphere ranging from Galapagos to the Antarctic.

Are Penguins in Antarctica?

Penguins are synonymous with Antarctica, yet only emperor and Adélie penguins are permanent residents of the continent. Other species, such as chinstrap, gentoo, and macaroni, breed on the Antarctic Peninsula or sub-Antarctic islands.

Can polar bears live in Antarctica?

Polar bears do not live in Antarctica. They never had. Polar bears live in the Arctic which occurs at the northernmost part of the planet. Antarctica on the other hand lies at the south pole of the Earth. Arctic and Antarctica shares many geographical features.

:> nope i helped

xx

firecat uwu

bearhunter [10]3 years ago
4 0
Yes. Animals such as certain species of penguin and polar bear.
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30pts!!!06.01 Simple Harmonic Motion Lab: Virtual Lab Simulation
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Answer:

Hello; I would like to say you that brainly is for short answers not very long answers if you want the answer you can contact brainly services

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If a hockey player starts from rest and accelerates at a rate of 2.1 m/s², how long does it take him to skate 30 m?
Vlada [557]

Answer:

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Explanation:

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3 years ago
Two antennas located at points A and B are broadcasting radio waves of frequency 96.0 MHz, perfectly in phase with each other. T
earnstyle [38]

Answer:

a)   Δφ = 1.51 rad , b)  x = 21.17 m

Explanation:

This is an interference problem, as they indicate that the distance AP is on the x-axis the antennas must be on the y-axis, the phase difference is

          Δr /λ = Δfi / 2π

          Δfi = Δr /λ 2π

          Δr = r₂-r₁

let's look the distances

         r₁ = 57.0 m

We use Pythagoras' theorem for the other distance

         r₂ = √ (x² + y²)

         r₂ = √(57² + 9.3²)

         r₂ = 57.75 m

The  difference is

         Δr = 57.75 - 57.0

         Δr = 0.75 m

Let's look for the wavelength

        c =  λ f

          λ = c / f

          λ = 3 10⁸ / 96.0 10⁶

          λ = 3.12 m

Let's calculate

         Δφ = 0.75 / 3.12 2π

         Δφ = 1.51 rad

b) for destructive interference the path difference must be λ/2, the equation for destructive interference with φ = π remains

           Δr = (2n + 1) λ / 2

           

For the first interference n = 0

           Δr = λ / 2

           Δr = r₂ - r₁

We substitute the values

        √ (x² + y²) - x = 3.12 / 2

Let's solve for distance x

          √ (x² + y²) = 1.56 + x

          x² + y² = (1.56 + x)²

          x² + y² = 1.56² + 2 1.56 x + x²

          y2 = 20.4336 +3.12 x

          x = (y² -20.4336) /3.12

          x = (9.3² -20.4336) /3.12

          x = 21.17 m

This is the distance for the first minimum

6 0
3 years ago
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How do you answer this. Need help ASAP. Offering 20 points !!!
Temka [501]

in this since your volume remains at a constant you'll need to use Gay-Lussacs law, p1/t1=p2/t2.

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just add 273 to your celcius

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t2= 315k

then you set up the equation

(3.0×10^6)/270= (x)(315)

you then cross multiply

(3.0×10^6)315=270x

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9.45×10^8=270x then you divide 270 o both sides to get

answer

3.5×10^6 n/m^2

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irina1246 [14]

Answer:

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As a result, the combined motion of the projectile has a curved trajectory (parabolic, more specifically). So the following options are correct:

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E.The path of the object is curved

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3 years ago
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