Answer:

Explanation:
<u><em>1. First determine the empirical formula.</em></u>
a) Base: 100 g of compound
mass atomic mass number of moles
g g/mol mol
C 26.06 12.011 26.06/12.011 = 2.17
H 13.13 1.008 13.13/1.008 = 13.03
N 60.81 14.007 60.81/14.007 = 4.34
b) Divide every number of moles by the smallest number: 2.17
mass number of moles proportion
C 2.17/2.17 1
H 13.03/2.17 6
N 4.34/2.17 2
c) Empirical formula

d) Mass of the empirical formula

<u><em>2. Molecular formula</em></u>
Since the mass of one unit of the empirical formula is equal to the molar mass of the compound, the molecular formula is the same as the empirical formula:

Answer:
Q = -14322.77 J
Explanation:
Given data:
Mass of water = 55.0 g
Initial temperature = 87.3°C
Final temperature = 25.0 °C
Heat given off = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water is 4.18 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 25.0 °C - 87.3°C
ΔT = - 62.3 °C
Q = 55.0 g×4.18 J/g.°C × - 62.3 °C
Q = -14322.77 J
The answer is A)radio waves, micro waves, visible light, x-rays
4
I can confirm that's the correct answer