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Sindrei [870]
2 years ago
7

A+B A=3i+4j-k B=5i+6j+2k​

Physics
1 answer:
OlgaM077 [116]2 years ago
7 0

\text{Given that,}\\\\\vec A =3 \hat i + 4 \hat j - \hat k ~ \text{and}~ \vec B = 5\hat i + 6 \hat j +2 \hat k \\ \\\text{Now,}\\\\\vec A + \vec B = 3 \hat i  +4 \hat j - \hat k + 5 \hat i + 6 \hat j + 2 \hat k\\\\~~~~~~~~~~=8 \hat i +10 \hat i + \hat k

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Air in a thundercloud expands as it rises. If its initial temperature is 292 K and no energy is lost by thermal conduction on ex
tiny-mole [99]

Answer:

Explanation:

It is a case of adiabatic expansion .

T_1V_1^{\gamma-1}=T_2V_2^{\gamma-1}

T₁ , T₂ are initial and final temperature , V₁ and V₂ are initial and final volume.

Given ,

V₂ = 3 V₁ and T₁ = 292 . γ for air is 1.4 .

( 3 )^{\gamma-1}= \frac{292}{ T_2}

( 3 )^{1.4-1}= \frac{292}{ T_2}

1.552 = 292 / T₂

T₂ = 188 K .

3 0
2 years ago
A rock is thrown straight upward off the edge of a balcony that is 5 m above the ground. The rock rises 10 m, then falls all the
Dvinal [7]
Displacement = distance and direction from the start-point
to the end-point, regardless of the route followed on the way.

From the throw to the 'plop', the displacement is 5 meters down.
7 0
3 years ago
Three parallel wires of length l each carry current Iin the same direction. They’re positioned at the vertices of an equilateral
cluponka [151]

Answer:

F = μi²l/πa

Explanation:

The magnetic force F on a length of wire, l carrying a current i in a magnetic field B is given by

F = Bilsinθ      

The magnetic field due to one wire of length, l carrying a current, i at a distance a from it is given by B = μi/2πa

So, the force on the first wire due to the second wire is F₁ = Bilsinθ = μiilsinθ/2πa = μi²lsinθ/2πa

the force on the first wire due to the third wire is F₂ = Bilsinθ = μiilsinθ/2πa = μi²lsinθ/2πa

Since the magnetic field due to the one wire is perpendicular to the length of the other wire its field acts upon, θ = 90

So, F₁ = μi²lsinθ/2πa = μi²lsin90/2πa = μi²l/2πa and

F₂ = μi²lsinθ/2πa = μi²lsin90/2πa = μi²l/2πa

Since the angle between F₁ and F₂ is 60° (since it is an equilateral triangle)

The resultant force F is thus

F = √(F₁² + F₂² + 2F₁F₂cos60°)

F = √(F₁² + F₂² + 2F₁F₂ × 0.5)

F = √(F₁² + F₂² + 2F₁F₂)   (since F₁ = F₂)

F = √(2F₁² + 2F₁²) = √(4F₁²)

F = 2F₁

F = 2μi²l/2πa

F = μi²l/πa

6 0
3 years ago
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The most abundant element in earth's continental crust (by weight) is____?
sashaice [31]
The answer is A. Oxygen
8 0
3 years ago
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Is direction the length of the route between two points ?
zepelin [54]

Answer:

No distance is the length between two routes

Explanation:

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