a. 0.137
b. 0.0274
c. 1.5892 g
d. 0.1781
e. 5.6992 g
<h3>Further explanation</h3>
Given
Reaction
2 C4H10 + 13O2 -------> 8CO2 + 10H2O
2.46 g of water
Required
moles and mass
Solution
a. moles of water :
2.46 g : 18 g/mol = 0.137
b. moles of butane :
= 2/10 x mol water
= 2/10 x 0.137
= 0.0274
c. mass of butane :
= 0.0274 x 58 g/mol
= 1.5892 g
d. moles of oxygen :
= 13/2 x mol butane
= 13/2 x 0.0274
= 0.1781
e. mass of oxygen :
= 0.1781 x 32 g/mol
= 5.6992 g
Answer:
7.68 × 10²⁴
Explanation:
Step 1: Calculate the mass of 1 molecule of the monomer CH₂CHCN
We will get the mass of the monomer by adding the masses of the elements.
mCH₂CHCN = 3 × mC + 3 × mH + 1 × mN
mCH₂CHCN = 3 × 12.01 amu + 3 × 1.01 amu + 1 × 14.01 amu = 53.07 amu
Step 2: Convert the mass of the monomer to grams
We will use the conversion factor 1 amu = 1.66 × 10⁻²⁴ g
53.07 amu × 1.66 × 10⁻²⁴ g/1 amu = 8.81 × 10⁻²³ g
Step 3: Calculate "n"
We will divide the mass of the polymer by the mass of the monomer.
n = 676.8 g / 8.81 × 10⁻²³ g = 7.68 × 10²⁴
Answer:
Percent by mass is calculated by tihis formula, Mass of solute (g) ÷ mass of solution (g)] × 100.
Explanation:
For example: if you have a solution 45% m/m (mass percentege), you have 45 g of solute in 100 g of solution.
