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3 years ago

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Question 16 of 25

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Alex Ar [27]3 years ago

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The answer to this question is A

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Propane, the gas used in barbeque grills, is made of carbon and hydrogen. Will the atoms that make up propane form covalent bond

Masteriza [31]

Hydrocarbons are molecules that contain only carbon and hydrogen. Due to carbon's unique bonding patterns, hydrocarbons can have single, double, or triple bonds between the carbon atoms. The names of hydrocarbons with single bonds end in "-ane," those with double bonds end in "-ene," and those with triple bonds end in "-yne". The bonding of hydrocarbons allows them to form rings or chains.

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An astronaut in her spacesuit weighs 300 lb on earth. What would her weight be on the moon?

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She would be 150 on the moon because the moon has half the mass of earth

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How many molecules of glucose are in 5. 72 grams of glucose c6h12o6?.

liq [111]

Answer:

5.72 g ( 1 mol / 180.16 g ) ( 6.022 x 10^23 molecules / mole ) = 1.90x10^23 molecules

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2 years ago

A sample of neon gas is at a temperature of 60°C and has a volume of 300 cm. What is the volume of the gas if it is heated to 10

elena55 [62]

Answer:

336.04 cm

Explanation:

T1 = 60+273 = 333K

T2 = 100+273 = 373K

V2 = (V1×T2)/T1

V2 = 300×373/333

V2 = 336.04 cm

6 0

3 years ago

Rusting of iron is a very common chemical reaction. It results in one form from Fe reacting with oxygen gas to produce iron (III

Vlada [557]

<u>Answer:</u> The given amount of iron reacts with 9.0 moles of $O_2$ and produce 6.0 moles of $Fe_2O_3$

<u>Explanation:</u>

We are given:

Moles of iron = 12.0 moles

The chemical equation for the rusting of iron follows:

$4Fe+3O_2\rightarrow 2Fe_2O_3$

<u>For oxygen gas:</u>

By Stoichiometry of the reaction:

4 moles of iron reacts with 3 moles of oxygen gas

So, 12.0 moles of iron will react with = $\frac{3}{4}\times 12.0=9.0mol$ of oxygen gas

<u>For iron (III) oxide:</u>

By Stoichiometry of the reaction:

4 moles of iron produces 2 moles of iron (III) oxide

So, 12.0 moles of iron will produce = $\frac{2}{4}\times 12.0=6.0mol$ of iron (III) oxide

Hence, the given amount of iron reacts with 9.0 moles of $O_2$ and produce 6.0 moles of $Fe_2O_3$

5 0

3 years ago