Ask question

Ask question

All categories

3 years ago

15

Lead ions can be removed from solution by precipitation with sulfate ions. Suppose a solution contains lead(II) nitrate.Write a

complete ionic equation to show the reaction of aqueous lead(II) nitrate with aqueous potassium sulfate to form solid lead(II) sulfate and aqueous potassium nitrate.

2 answers:

Alexxx [7]3 years ago

6 0

The equation:
Pb(NO3)2 + K2SO4 = PbSO4 + 2KNO3
The ionic equation:
$Pb^{2+} + SO4^{2-} = PbSO4$

morpeh [17]3 years ago

3 0

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of lead (II) nitrate and potassium sulfate is given as:

$Pb(NO_3)_2(aq.)+K_2SO_4(aq.)\rightarrow PbSO_4(s)+2KNO_3(aq.)$

Ionic form of the above equation follows:

$Pb^{2+}(aq.)+2NO_3^-(aq.)+2K^+(aq.)+SO_4^{2-}(aq.)\rightarrow PbSO_4(s)+2K^+(aq.)+2NO_3^-(aq.)$

As, potassium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$Pb^{2+}(aq.)+SO_4^{2-}(aq.)\rightarrow PbSO_4(s)$

Hence, the net ionic equation is written above.

You might be interested in

Hydrogen is 99% 1H, 0.8% 2H, and 0.2% 3H. Calculate its average atomic mass.

AlekseyPX

The average atomic mass of hydrogen (99% H-1, 0.8% H-2, and 0.2% H-3) is 1.012 amu.

The average atomic mass of hydrogen can be calculated with the following equation:

$A = m_{H-1}\%_{H-1} + m_{H-2}\%_{H-2} + m_{H-3}\%_{H-3}$

Where:

$m_{H-1}$ : is the mass of protium (H-1) = 1

$m_{H-2}$ : is the <em>mass</em> of deuterium (H-2) = 2

$m_{H-3}$ : is the <em>mass </em>of tritium (H-3) = 3

$\%_{H-1}$ : is the abundance percent of H-1 = 99%

$\%_{H-2}$ : is the <em>abundance percent</em> of H-2 = 0.8%

$\%_{H-3}$ : is the <em>abundance percent</em> of H-3 = 0.2%

The average atomic mass is:

$A = 1*99\% + 2*0.8\% + 3*0.2\%$

Changing all the <u>percent values</u> into <u>decimal ones</u>, we have:

$A = 0.99 + 2*0.008 + 3*0.002 = 1.012$

Therefore, the average atomic mass of hydrogen is 1.012 amu.

Learn more about average atomic mass here brainly.com/question/8575403?referrer=searchResults

I hope it helps you!

6 0

2 years ago

Phosphoric acid is a triprotic acid ( K a1 = 6.9 × 10 − 3 Ka1=6.9×10−3, K a2 = 6.2 × 10 − 8 Ka2=6.2×10−8, and K a3 = 4.8 × 10 −

irina1246 [14]

<u>Answer:</u> To calculate the pH of the buffer composed of $H_2PO_4^-\text{ and }HPO_4^{-2}$ , we use the $K_a2$

<u>Explanation:</u>

Phosphoric acid is a triprotic acid and it will undergo three dissociation reaction each having their respective dissociation constants.

The chemical equation for the first dissociation reaction follows:

$H_3PO_4\rightleftharpoons H_2PO_4^-+H^+;K_a1=6.9\times 10^{-3}$

The chemical equation for the second dissociation reaction follows:

$H_2PO_4^-\rightleftharpoons HPO_4^{2-}+H^+;K_a2=6.2\times 10^{-8}$

The chemical equation for the third dissociation reaction follows:

$HPO_4^{2-}\rightleftharpoons PO_4^{3-}+H^+;K_a3=4.8\times 10^{-13}$

To form a buffer composed of $H_2PO_4^-\text{ and }HPO_4^{-2}$ , we use the $K_a$ of second dissociation process

To calculate the $pK_a$ , we use the equation:

$pK_a=-\log (K_a)\\\\pK_a=-\log(6.2\times 10^{-8})\\\\pK_a=7.21$

To calculate the pH of buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a2+\log(\frac{[\text{conjugate base}]}{[\text{weak acid}]})$

$pH=pK_a2+\log(\frac{[HPO_4^{2-}]}{[H_2PO_4^-]})$

We are given:

$pK_a2$ = negative logarithm of second acid dissociation constant of phosphoric acid = 7.21

$[HPO_4^{2-}]$ = concentration of conjugate base

$[H_2PO_4^{-}]$ = concentration of weak acid

Hence, to calculate the pH of the buffer composed of $H_2PO_4^-\text{ and }HPO_4^{-2}$ , we use the $K_a2$

3 0

4 years ago

How is heavey water different from normal water

earnstyle [38]

Answer:

Oxygen in heavy water, or d20, have an extra neutron, and it contains a higher portion of hydrogen. The extra neutron makes d20 (heavy water) about 10% denser than normal H20 (water).

Hope this helps!

Brainliest would be appreciated!

5 0

3 years ago

If the hydrogen ion concentration of an unknown solution is 4.56E-7, what is its pH and will this form an acid or a base?

Inessa05 [86]

If the hydrogen ion concentration of an unknown solution is 4.56E-7, the pH of the solution will be 6.34 and it will form an acid.

<h3>How to calculate pH from H+?</h3>

The pH, which is the power of hydrogen, can be calculated from the hydrogen ion concentration using the following expression:

pH = - log [H+]

According to this question, the hydrogen ion concentration of an unknown solution is 4.56E-7. The pH is as follows:

pH = - log [4.56E-7]

pH = 6.34

Therefore, If the hydrogen ion concentration of an unknown solution is 4.56E-7, the pH of the solution will be 6.34 and it will form an acid.

Learn more about pH at: brainly.com/question/15289741

#SPJ1

8 0

2 years ago

Which of the following compounds would have the highest boiling point?

grin007 [14]

Answer:a. 1-propanol,

Explanation:

Boiling point depends on the relative molecular mass of the compound and the kind of intermolecular interactions present in the substance. 1-propanol has a relative molecular mass of 60 and posses strong intermolecular hydrogen bonding. The presence of hydrogen bonding is known to lead to an increase in boiling point. As a result of this, it is obvious that 1-propanol has the highest boiling point among other compounds in the list.

6 0

4 years ago