All categories

2 years ago

A ball with an initial velocity of zero is dropped from a table onto the ground. After 2 s, the

Physics

2 answers:

WINSTONCH [101]2 years ago

7 0

Answer:

Explanation:

I don't know 200000000000000000000

GenaCL600 [577]2 years ago

5 0

Initial velocity=u=0m/s
Acceleration=a=10m/s^2
Time=t=2s

Final velocity=v

$\\ \sf\longmapsto v=u+at$

$\\ \sf\longmapsto v=0+10(2)$

$\\ \sf\longmapsto v=20m/s$

You might be interested in

2) [25 pts] The bob of mass m=5 kg shown in the figure is being held by a force F. If the angle is 0⃗

Colt1911 [192]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The tension is $T = 48.255 \ N$

The time taken is $t = 0.226 \ s$

The position for maximum velocity is

S = 0

The maximum velocity is $V_{max} =0.384 \ m/s$

Explanation:

The free body for this question is shown on the second uploaded image

From the question we are told that

The mass of the bob is $m_b = 5 \ kg$

The angle is $\theta = 10^o$

The length of the string is $L = 0.5 \ m$

The tension on the string is mathematically represented as

$T = mg cos \theta$

substituting values

$T = 5 * 9.8 cos(10)$

$T = 48.255 \ N$

The motion of the bob is mathematically represented as

$S = A sin (w t + \frac{\pi }{2} )$

=> $S = A sin (wt)$

Where $w$ is the angular speed

and $\frac{\pi}{2}$ is the phase change

At initial position S = 0

So $wt = cos^{-1} (0)$

$wt = 1$

Generally $w$ can be mathematically represented as

$w = \frac{2 \pi }{T}$

Where T is the period of oscillation which i mathematically represented as

$T = 2 \pi \sqrt{\frac{L}{g} }$

$t = \frac{1}{w}$

$t = \frac{T}{2 \pi}$

$t = \sqrt{\frac{L}{g} }$

substituting values

$t = \sqrt{\frac{0.5}{9.8} }$

$t = 0.226 \ s$

Looking at the equation

$wt = 1$

We see that maximum velocity of the bob will be at S = 0

i. e $w = \frac{1}{t}$

The maximum velocity is mathematically represented as

$V_{max} = w A$

Where A is the amplitude which is mathematically represented as

$A = L sin \theta$

$V_{max} = \frac{2 \pi }{T } L sin \theta$

$V_{max} = \frac{2 \pi }{2 \pi } \sqrt{\frac{g}{L} } L sin \theta$ Recall $T = 2 \pi \sqrt{\frac{L}{g} }$

$V_{max} = \sqrt{gL} sin \theta$

substituting values

$V_{max} = \sqrt{9.8 * 0.5 } sin (10)$

$V_{max} =0.384 \ m/s$

6 0

2 years ago

Light traveling through air encounter a second medium which slows the light to 2.7 x 10^8. What is the index of the medium?

kozerog [31]

Answer:

1.11

Explanation:

The index of the medium can be calculated using below formula

V= c/ n ............eqn(1)

Where V= velocity of the light is reduced to while traveling through the second medium= 2.7 x 10^8 m/s

n= index of the medium

c= speed of light= 3 x 10^8 m/s

Substitute for the values in eqn(1)

2.7 x 10^8 = (3 x 10^8 m/s)/ n

Making " n" subject of the formula, we have

n= (3 x 10^8 )/(2.7 x 10^8)

n= 1.11

Hence, the index of the medium is 1.11

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%7B%5Chuge%5Cfcolorbox%7Bblue%7D%7Bblack%7D%7B%5Cpink%7B%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%5

kumpel [21]

the branch of optics that studies interference, diffraction, polarization, and other phenomena for which the ray approximation of geometric optics is not valid.

3 0

2 years ago

Fission is the process of creating energy by

Colt1911 [192]

<h2>Answer: The separation of the components of the nucleous of the atom </h2><h2> </h2>

The n<u>uclear fission</u> consists of dividing a heavy nucleus into two or more lighter or smaller nuclei, by means of the <u>bombardment with neutrons to make it unstable. </u>

Then, with this division a great release of energy occurs and the emission of two or three neutrons, other particles and gamma rays.

It should be noted that in the process, the emitted neutrons can interact with new fissionable nuclei that will emit new neutrons and so on. Effect better known as chain reaction.

3 0

3 years ago

Oh no! The Hulk just fell off the Empire State Building! Calculate how long it took him to fall straight down from the top of th

nekit [7.7K]

Answer:it takes approximately 148.8 seconds to achieve. The average person in a free-fall will hit the ground going at 9.66 m/s from the top of the Empire State Building.

Explanation:

3 0

2 years ago