A kicked soccer ball eventually comes to rest. What force causes this? ce

How many liquids are found on the periodic table? 1

Nookie1986 [14]

There are six liquids found on the periodic table.

1. Bromine

2. Mercury

3. Caesium

4. Gallium

5. Rubidium

6. Francium

3 0

3 years ago

How many molecules of co2,h2o,c3h8, and o2 will be present if the reaction goes to completion?

Nadya [2.5K]

Let initially there are 10 molecules of O2 and 3 molecules of C3H8 present

The reaction will be

C3H8(g) + 5O2(g) ----> 3CO2(g) + 4H2O

so here oxygen molecules are limiting as for 3 molecules of C3H8 we need 15 molecules of O2

now the given 10 molecules of O2 will react with only 2 molecules of C3H8 and they will form six molecules of CO2 and 8 molecules of H2O

Hence answer is

molecules of CO2 formed = 6

Molecules of H2O formed = 8

molecules of C3H8 left = 1

molecules of O2 left = 0

7 0

3 years ago

Read 2 more answers

Sodium nitrate is used in fertilizers, explosives, and glass manufacturing. Give the formula for this compound

krek1111 [17]

Explanation:

The molecular formula for Sodium Nitrate is NaNO3. The SI base unit for amount of substance is the mole. 1 grams Sodium Nitrate is equal to 0.011765443644878 mole.

7 0

3 years ago

Choose all true statements about the water molecule: Choose all true statements about the water molecule: Bonding between the ox

amm1812

Answer: Water is a permanent electric dipole, having permanent charge separation.

Explanation:

Hydrogen bonding is an intermolecular force having partial ionic-covalent character.

In $H_2O$ , O is a highly electronegative atom attached to a H atom through a covalent bond. The oxygen atoms being more electronegative gets partial negative charge and H atom gets partial positive charge. Thus water is permanent electric dipole.

Hydrogen bonding takes place between a hydrogen atom (attached with an electronegative atom O) and an electronegative atom (O).

4 0

3 years ago

Assume that the test tube shown started out having 10.00 g of mercury(II) oxide. After heating the test tube briefly, you find 1

anyanavicka [17]

This problem is providing information about the initial mass of mercury (II) oxide (10.00 g) which is able to produce liquid mercury (8.00 g) and gaseous oxygen and asks for the resulting mass of the latter, which turns out to be 0.65 g after doing the corresponding calculations.

Initially, it is given a mass of 10.00 g of the oxide and 1.35 g are left which means that the following mass is consumed:

$m_{HgO}^{consumed}=10.00g-1.35 g=8.65 g$

Now, since 8.00 grams of liquid mercury are collected, it is possible to calculate the grams of oxygen that were produced, by considering the law of conservation of mass, which states that the mass of the products equal that of the reactants as it is nor destroyed nor created. In such a way, the mass of oxygen turns out to be:

$m_{O_2}=8.65g-8.00g=0.65g$

Learn more:

3 0

2 years ago