An empirical formula is the "reduced" version of a molecular formula. For example, CH3 is the empirical formula for C2H6, C3H9, C4H12, and so forth. The difference in subscripts between an empirical formula and molecular formula is given by the constant n. If n is a whole number, this means the numerator is the molecular formula. So the answer is D. <span>subscript of C in molecular formula = n  subscript of C in empirical formula. This can be rewritten as:
n = subscript of C in molecular formula/subscript of C in empirical formula</span>
Isotopes are variants atoms of the same element, having same number of atomic(proton) number but different number of neutrons and mass number.
Considering iron-60
- The atomic number which also equals the number of protons for the element iron as can be seen on the periodic table is 26
- The name iron-60 also tells us that this particlar isotope's mass number is 60.
- The chemical symbol for Iron is Fe
Now expressing as an isotope iron-60 becomes ⁶⁰₂₆Fe ( very unstable )
Other stable isotopes of Iron include ⁵⁴₂₆Fe , ⁵⁶₂₆Fe, ⁵⁷₂₆Fe and ⁵⁸₂₆Fe
See more here: brainly.com/question/11236150
Answer:
i think i like 14 or 8 atom
Explanation:
<span>• Benzene has the formula of C6H<span>6 </span>whereas cyclohexane has the formula of C6H<span>12.
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Benzene is an aromatic compound but cyclohexane is not aromatic.
Benzene is an unsaturated molecule, but cyclohexane is saturated.
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Carbon atoms in the benzene ring have sp2 hybridization where carbon atoms in the cyclohexane have sp3 hybridization.</span>
Benzene has a planar structure whereas cyclohexane has chair conformations.<span>
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First, we need the no.of moles of O2 = mass/molar mass of O2
= 55 g / 32 g/mol
= 1.72 mol
from the balanced equation of the reaction:
2H2 (g) + O2(g) → 2H2O(g)
we can see that the molar ratio between O2: H2O = 1: 2
So we can get the no.of moles of H2O = 2 * moles of O2
= 2 * 1.72 mol
= 3.44 mol
So by substitution by this value in ideal gas formula:
PV = nRT
when P = 12.4 atm & n H2O = 3.44 mol & R= 0.0821 & T = 85 + 273=358K
12.4 atm *V = 3.44 * 0.0821 * 358 = 8.15 L
∴ V ≈ 8.2 L
