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Lyrx [107]
2 years ago
9

A girl and her dog are running away from their house. The dog has a mass of 20kg. The girl has a mass of 60 kg.

Chemistry
1 answer:
zloy xaker [14]2 years ago
6 0

Answer: 160 joules

Explanation: the formula for kinetic energy is KE= 1/2 x m x v squared (ke being kinetic energy, m being mass of the object and v being velocity). To find the kinetic energy, you must plug in the given values. KE= 1/2 x 20 x 4 squared. 4 squared is 16, 16 times 20 is 320 and 1/2 of that is 160- so that’s your answer.

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What is the percent composition of N H S O in (NH4)2SO4
Lena [83]

Answer:

The percent composition is 21% N, 6% H, 24% S and 49% O.

Explanation:

1st) The molar mass of (NH4)2SO4 is 132g/mol, and it represents the 100% of the mass composition.

In 1 mole of (NH4)2SO4, there are:

- 2 moles of N.

- 8 moles of H.

- 1 mole of S.

- 4 moles of O.

2nd) It is necessary to calculate the mass of each element, multiplying its molar mass by the number of moles:

- 2 moles of N (14g/mol) = 28g

- 8 moles of H (1g/mol) = 8g

- 1 mole of S (32g/mol) = 32g

- 4 moles of O (16g/mol) = 64g

3rd) With a mathematical rule of three we can calculate the percent composition of each element in the molecule of (NH4)2SO4:

\begin{gathered} \text{ Nitrogen:} \\ 132g-100\% \\ 28g-x=\frac{28g*100\%}{132g} \\ x=21\% \end{gathered}\begin{gathered} \text{ Hydrogen:} \\ 132g-100\operatorname{\%} \\ 8g-x=\frac{8g*100\operatorname{\%}}{132g} \\ x=6\% \end{gathered}\begin{gathered} \text{ Sulfur:} \\ 132g-100\operatorname{\%} \\ 32g-x=\frac{32g*100\operatorname{\%}}{132g} \\ x=24\% \end{gathered}\begin{gathered} \text{ Oxygen:} \\ 100\%-21\%-6\%-24\%=49\% \\  \\  \end{gathered}

In this case, we can calculate the percent composition of Oxygen by subtracting the other percentages, since the total must be 100%.

So, the percent composition is 21% N, 6% H, 24% S and 49% O.

8 0
1 year ago
An electrochemical cell has the following standard cell notation.
icang [17]

The cell notation is:

Mg(s)|Mg^{+2}(aq)||Ag^{+}(aq)|Ag(s)

here in cell notation the left side represent the anodic half cell where right side represents the cathodic half cell

in anodic half cell : oxidation takes place [loss of electrons]

in cathodic half cell: reduction takes place [gain of electrons]

1) this is a galvanic cell

2) the standard potential of cell will be obtained by subtracting the standard reduction potential of anode from cathode

E^{0}_{Mg}=-2.38V

E^{0}_{Ag}=+0.80V

Therefore

E^{0}_{cell}=0.80-(-2.38)=+3.18V

3) as the value of emf is positive the reaction will be spontaneous as the free energy change of reaction will be negative

ΔG^{0}=-nFE^{0}

As reaction is spontaneous and there will be conversion of chemical energy to electrical energy it is a galvanic cell.

7 0
3 years ago
Please help! Which Zeros are significant in the measurement .0506010 kg?
Vitek1552 [10]
It would be a,b,c as the answer. hope this helps!
7 0
3 years ago
If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K and then I raise the pressu
mixas84 [53]

Answer:

The answer to your question is V2 = 29.6 l

Explanation:

Data

Pressure 1 = P1 = 12 atm

Volume 1 = V1 = 23 l

Temperature 1 = T1 = 200 °K

Pressure 2 = 14 atm

Volume 2 = V2 = =

Temperature 2 = T2 = 300°K

Process

1.- To solve this problem use the Combine gas law.

             P1V1/T1 = P2V2/T2

-Solve for V2

             V2 = P1V1T2 / T1P2

2.- Substitution

             V2 = (12)(23)(300) / (200)(14)

3.- Simplification

             V2 = 82800 / 2800

4.- Result

            V2 = 29.6 l

5 0
3 years ago
1) How much energy would be required to melt 15.0 g of ice at 0°C?
DerKrebs [107]

Answer:

5010J

Explanation:

The following data were obtained from the question:

Mass (m) = 15g

Heat of fusion (ΔHf) = 334J/g

Heat required (Q) =..?

The heat energy required to melt the ice can be obtained as follow:

Q = m·ΔHf

Q = 15 x 334

Q = 5010J

Therefore, the heat energy required to melt the ice is 5010J.

8 0
3 years ago
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