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vitfil [10]
3 years ago
8

A 2.0 L aqueous solution contains a total of 3.0 moles of dissolved NaCl. Determine the molarity of the solution. M = Moles of s

olute/Liters of solution
A. 1.0 moles
B.1.5 moles
C. 2.0 M
D. 1.5 M
Chemistry
1 answer:
BARSIC [14]3 years ago
8 0
Answer should be 1.5 M given that M is the SI unit for molarity!
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3 years ago
The following pairs of soluble solutions can be mixed. In some cases, this leads to the formation of an insoluble precipitate. D
Westkost [7]

Answer:

a) K_{2} S and NH_{4} Cl :

There are no insoluble precipitate forms.

b) Ca Cl_{2} and (NH_{4} )_{2} Co_{3} :

There are the insoluble precipitates of CaCo_{3}  forms.

c) Li_{2}S and MnBr_{2} :

There are the insoluble precipitates of MnS  forms.

d) Ba(No_{3} )_{2} and Ag_{2} So_{4} :                        

As Ag_{2} So_{4} is insoluble, therefore no precipitate forms.

e) Rb_{2}Co_{3} and NaCl:

There are no insoluble precipitates forms.

Explanation:

a)

Solubility rule suggests:- K_{2} S ⇒ soluble, NH_{4} Cl ⇒ soluble.

                                          KCl ⇒ soluble, (NH_{4})_{2} S  ⇒ soluble.

There are no insoluble precipitate forms.

b)

Solubility rule suggests:- Ca Cl_{2} ⇒ soluble, (NH_{4} )_{2} Co_{3} ⇒ soluble.

                                        CaCo_{3} ⇒ insoluble, NH_{4} Cl  ⇒ soluble.

There are the insoluble precipitates of CaCo_{3}  forms.

c)

Solubility rule suggests:- Li_{2}S ⇒ soluble, MnBr_{2} ⇒ soluble.

                                        LiBr ⇒ soluble, MnS  ⇒ insoluble.

There are the insoluble precipitates of MnS  forms.

d)

Solubility rule suggests:- Ba(No_{3} )_{2} ⇒ soluble, Ag_{2} So_{4} ⇒insoluble.

                                     

As Ag_{2} So_{4} is insoluble, therefore no precipitate forms.

e)

Solubility rule suggests:- Rb_{2}Co_{3} ⇒ soluble, NaCl ⇒ soluble.

                                        RbCl ⇒ soluble, Na_{2} Co_{3}  ⇒ soluble.

There are no insoluble precipitates forms.

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Which of the following is NOT a reason why chemical bonds are important? *
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Answer:

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