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3 years ago

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Implement a function with signature transfer(S, T) that transfers all elements from stack S onto stack T, so that the element th

at starts at the top
of S is the first to be inserted onto T, and the element at the bottom of S
ends up at the top of T.

1 answer:

dmitriy555 [2]3 years ago

8 0

I’ve took engineering but never learnt this lol

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zheka24 [161]

Answer:

And Im still going with B..

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3 years ago

A battery is connected to a resistor. Increasing the resistance of the resistor will __________. A battery is connected to a res

belka [17]

Answer: the increase in the external resistor will affect and decrease the current in the circuit.

Explanation: A battery has it own internal resistance, r, and given an external resistor of resistance, R, the equation of typical of Ohm's law giving the flow of current is

E = IR + Ir = I(R + r)........(1)

Where IR is the potential difference flowing in the external circuit and Or is the lost voltage due to internal resistance of battery. From (1)

I = E/(R + r)

As R increases, and E, r remain constant, the value (R + r) increases, hence the value of current, I, in the external circuit decreases.

8 0

3 years ago

A pump with a power of 5 kW (pump power, and not useful pump power) and an efficiency of 72 percent is used to pump water from a

almond37 [142]

Answer:

a) The mass flow rate of water is 14.683 kilograms per second.

b) The pressure difference across the pump is 245.175 kilopascals.

Explanation:

a) Let suppose that pump works at steady state. The mass flow rate of the water ( $\dot m$ ), in kilograms per second, is determined by following formula:

$\dot m = \frac{\eta \cdot \dot W}{g\cdot H}$ (1)

Where:

$\dot W$ - Pump power, in watts.

$\eta$ - Efficiency, no unit.

$g$ - Gravitational acceleration, in meters per square second.

$H$ - Hydrostatic column, in meters.

If we know that $\eta = 0.72$ , $\dot W = 5000\,W$ , $g = 9.807\,\frac{m}{s^{2}}$ and $H = 25\,m$ , then the mass flow rate of water is:

$\dot m = 14.683\,\frac{kg}{s}$

The mass flow rate of water is 14.683 kilograms per second.

b) The pressure difference across the pump ( $\Delta P$ ), in pascals, is determined by this equation:

$\Delta P = \rho\cdot g\cdot H$ (2)

Where $\rho$ is the density of water, in kilograms per cubic meter.

If we know that $\rho = 1000\,\frac{kg}{m^{3}}$ , $g = 9.807\,\frac{m}{s^{2}}$ and $H = 25\,m$ , then the pressure difference is:

$\Delta P = 245175\,Pa$

The pressure difference across the pump is 245.175 kilopascals.

4 0

3 years ago

The Reynolds number is a dimensionless group defined for a fluid flowing in a pipe as Re Durho/μ whereD is pipe diameter, u is f

Gala2k [10]

Answer:

the flow is turbulent

Explanation:

The Reynolds number is given by

Re=ρVD/μ

where

V=fluid speed=0.48ft/s=0.146m/s

D=diameter=2.067in=0.0525m

ρ=density=0.805g/cm^3=805Kg/m^3

μ=0.43Cp=4.3x10^-4Pas

Re=(805)(0.146)(0.0525)/4.3x10^-4=14349.59

Re>2100 the flow is turbulent

Note: if you do not want to use a calculator you can use the graphs to calculate the Reynolds number according to their properties

8 0

3 years ago

a) A 10-mm-diameter Brinell hardness indenter produced an indentation 2.50 mm in diameter in a steel alloy when a load of 1000 k

Vinvika [58]

Answer:

a) $HB = 200.484$ , b) $d \approx 1.453\,mm$

Explanation:

The Brinell hardness can be determined by using this expression:

$HB = \frac{2\cdot P}{\pi\cdot D^{2}}\cdot \left(\frac{1}{1-\sqrt{1-\frac{d^{2}}{D^{2}} } } \right)$

Where $D$ and $d$ are the indenter diameter and the indentation diameter, respectively.

a) The Brinell hardness is:

$HB = \frac{2\cdot (1000\,kgf)}{\pi\cdot (10\,mm)^{2}} \cdot \left[\frac{1}{1-\sqrt{1-\frac{(2.50\,mm)^{2}}{(10\,mm)^{2}} } } \right]$

$HB = 200.484$

b) The diameter of the indentation is obtained by clearing the corresponding variable in the Brinell formula:

$d = D\cdot \sqrt{1-(1-\frac{2\cdot P}{\pi\cdot HB \cdot D^{2}} )^{2}}$

$d = (10\,mm)\cdot\sqrt{1-\left[1-\frac{2\cdot (500\,kgf)}{\pi\cdot (300)\cdot (10\,mm)^{2}} \right]^{2}}$

$d \approx 1.453\,mm$

5 0

3 years ago

Read 2 more answers