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lions [1.4K]
3 years ago
15

Implement a function with signature transfer(S, T) that transfers all elements from stack S onto stack T, so that the element th

at starts at the top
of S is the first to be inserted onto T, and the element at the bottom of S
ends up at the top of T.
Engineering
1 answer:
dmitriy555 [2]3 years ago
8 0
I’ve took engineering but never learnt this lol
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Cell phones require powerful batteries in orde to work effectively. Which activity is best described as an engineering endeavor
natta225 [31]
Where are the options?
8 0
3 years ago
To protect their employees from caught-in and -between hazards, what must employers do?
marusya05 [52]

Answer:

Employers must comply with OSHA's regulations to safeguard workers from caught-in or -between dangers, which include, but are not limited to, the following:

• Protect power tools and other equipment with moving parts with guards.

• Support, secure, or otherwise make safe any equipment that has pieces that workers could become entangled in.

· Take precautions to avoid workers being crushed by tipped-over heavy machinery.

• Take precautions to avoid pinning workers between equipment and a solid object.

• Provide workers with protection when trenching and excavating.

• Provide ways to prevent constructions, such as scaffolds, from collapsing.

Explanation:

5 0
3 years ago
Beryllium (Be) has an HCP unit cell for which the ratio of the lattice parameters c/a is 1.568. If the radius of the Be atom is
sweet-ann [11.9K]

Answer:

Unit cell volume will be

4.866*10^{-2}nm^{3}

8 0
3 years ago
I really need some help here!
Virty [35]

Explanation:

<h3>1.*Frame Structure have joins which keep them together whereas Shell Structure have no joins.</h3><h3>*Shell Structure usually only support their own weight whereas Frame Structure support others weight as well as themselve.</h3>
7 0
3 years ago
If the specific surface energy for magnesium oxide is 1.0 J/m2 and its modulus of elasticity is (225 GPa), compute the critical
lubasha [3.4K]

Answer:critical stress= 20.23 MPa

Explanation:

Since there was an internal crack, we will divide the length of the internal crack by 2

Length of internal crack, a = 0.7mm,

Half length = 0.7mm/2= 0.35mm  changing to meters becomes

0.35/ 1000= 0.35 x 10 ^-3m

The formulae for critical stress is calculated using

σC = (2Eγs /πa) ¹/₂

σC = critical stress=?

Given

E= Modulus of Elasticity= 225GPa =225 x 10 ^ 9 N/m²

γs= Specific surface energy = 1.0 J/m2 = 1.0 N/m

a= Half Length of crack=0.35 x 10 ^-3m

σC= (2 x 225 x 10 ^ 9 N/m² x 1.0 N/m /π x 0.35 x 10 ^-3m)¹/₂

=(4.5 x 10^11/π x 0.35 x 10 ^-3)¹/₂

=(4.0920 x10 ^14)¹/₂

σC=20.23 x10^6 N/m² = 20.23 MPa

​  

​

8 0
3 years ago
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