All categories

3 years ago

Calculate the average kinetic energies of CH4g and N2 g molecules at 273 K and 546K

Chemistry

1 answer:

kaheart [24]3 years ago

7 0

Answer:

Average kinetic energy of gases, which is derived from the RMS (root mean square speed) and KE equation, can be solved as:

It appears that the average KE of gases is dependent on the temperature which means that all gases will have the same KE as long the temperature is the same

You might be interested in

A small amount of a solid is added to water. The observation made after fifteen minutes is shown in the figure. Which of these s

natulia [17]

Answer:

B) sand

Explanation:

A) Oil is a wrong choice because it is a liquid not a solid and also if it is oil, it will float over the water surface as a droplets.

B) Sand is the right choice, because sand is a solid and it does not dissolve in water and stabilizes at the bottom.

C) Sugar is a wrong choice, because small amount of sugar will dissolve in water and be a homogeneous solution and does not appear as a particles.

D) Wood ships is also a wrong choice, even it is a solid and does not dissolve in water, but it will float over the water surface.

4 0

3 years ago

Carbon dioxide (CO2) is the gas that is mainly responsible for global warming (the greenhouse effect). The burning of fossil fue

Nesterboy [21]

Answer:

$1.7\cdot 10^{15} g$

Explanation:

Glucose reacts with oxygen do produce carbon dioxide and water:

$C_6H_12O_6 (s) + 6 O_2 (g)\rightarrow 6 CO_2 (g) + 6 H_2O (l)$

Given a daily mass of glucose:

$m_1 = 5.0\cdot 10^2 g$

Find moles of glucose:

$n_1 = {5.0\cdot 10^2 g}{180.156 g/mol} = 2.775 mol$

From stoichiometry of this equation, moles of carbon dioxide can be found by multiplying this amount by 6:

$n_2 = 2.775 mol\cdot 6=16.65 mol$

Convert this into mass using the molar mass of carbon dioxide:

$m_2 = 16.65 mol\cdot 44.01 g/mol = 732.8 g$

This is the mass of carbon dioxide per person per day. Multiply by the population and by the number of days to get the total mass:

$732.8 \frac{g}{person\cdot day}\cdot 365 days\cdot 6.5\cdot 10^9 people = 1.7\cdot 10^{15} g$

5 0

3 years ago

In what two places minerals are form?

larisa [96]

In earths surface or the bottom of the Ocean

3 0

3 years ago

1.42 g H2 is allowed to react with 10.4 g N2 , producing 2.14 g NH3 . Part A What is the theoretical yield in grams for this rea

Bad White [126]

Taking into account the reaction stoichiometry, the theorical yield for the reaction is 8.0467 grams of NH₃.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

3 H₂ + N₂ → 2 NH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

H₂: 3 moles
N₂: 1 mole
NH₃: 2 moles

The molar mass of the compounds is:

H₂: 2 g/mole
N₂: 28 g/mole
NH₃: 17 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

H₂: 3 moles ×2 g/mole= 6 grams
N₂: 1 mole ×28 g/mole= 28 grams
NH₃: 2 moles ×17 g/mole= 34 grams

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 28 grams of N₂ reacts with 6 grams of H₂, 10.4 grams of N₂ reacts with how much mass of H₂?

$mass of H_{2} =\frac{10.4 grams of N_{2}x 6 grams of H_{2} }{28 grams of N_{2}}$

<u><em>mass of H₂= 2.2286 grams</em></u>

But 2.2286 grams of H₂ are not available, 1.42 grams are available. Since you have less mass than you need to react with 10.4 grams of N₂, H₂ will be the limiting reagent.

<h3>Definition of theorical yield</h3>

The theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

<h3>Theoretical yield in this case</h3>

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 6 grams of H₂ form 34 grams of NH₃, 1.42 grams of H₂ form how much mass of NH₃?

$mass of NH_{3} =\frac{1.42 grams of H_{2} x 34 grams of NH_{3}}{6grams of H_{2} }$