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olchik [2.2K]
2 years ago
13

A 75 Kg skateboarder is riding downhill, exerting 25 N. What is their acceleration?

Chemistry
1 answer:
Hunter-Best [27]2 years ago
4 0

Answer:

<h3>The answer is 0.33 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

where

m is the mass

f is the force

a is the acceleration

From the question

f = 25 N

m = 75 kg

We have

a =  \frac{25}{75}   =  \frac{1}{3}  \\  = 0.333333333...

We have the final answer as

<h3>0.33 m/s²</h3>

Hope this helps you

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Which of the following salts will be less soluble in 0.10 M NaCl than it is in pure water?
MariettaO [177]

The less soluble salt : PbCl₂

<h3>Further explanation</h3>

Given

0.1 M NaCl

Required

The less soluble salt

Solution

If we see from the answer option, the salt that is more difficult to dissolve in NaCl is PbCl₂ because it has the same ion (Cl)

When PbCl₂ is dissolved in water, ionization will occur

PbCl₂ ⇒ Pb²⁺+ 2Cl⁻

So, when dissolved in NaCl, NaCl itself will be ionized

NaCl ⇒ Na⁺ + Cl⁻

Based on the principle of equilibrium, the addition of an ion (one of the ions is enlarged), the reaction will shift towards the ion that was not added. In addition to this Cl ion, the reaction will shift to the left so that the solubility of PbCl₂ will decrease (the reaction to the right decreases)

8 0
2 years ago
Anyone tryna help mee
devlian [24]

Answer:

It is a solid

4 0
2 years ago
The normal boiling point of methanol is 64.7∘c and the molar enthalpy of vaporization of 71.8kj/mol. the value of δs when 1.11 m
maxonik [38]
The answer is 236.5 J/K

According to Δ G formula:

ΔG = ΔH - TΔS

when ΔG is the change in free energy (KJ)

and ΔH is the change in enthalpy (KJ)= ΔHvap * moles

                                                              = 71.8 KJ/mol * 1.11 mol
                                                             
                                                              =   79.7 KJ

and T is the absolute temperature (K)= 64 °C + 273°C = 337 K

Δ S is the change in entropy  KJ/K

by substitution:

when at equilibrium ΔG = 0 

∴ΔS = ΔH / T

       =79.7 KJ/ 337 K

     = 0.2365 KJ/K

     = 236.5 J/K


6 0
3 years ago
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Luden [163]

Answer:

I don’t want to download a pdf that I don’t know what it is…

Also, brainly strictly says that we can’t post questions about a test or quiz that is found in school…

Explanation:

5 0
2 years ago
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Everything in outer space including stars, planets, and galaxies
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Answer:

Universe.

Explanation:

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