The density of the gas can be given by the mass of the substance and its volume. A 4084 gms of ammonia has a volume of 5.99 L.
<h3>What is STP?</h3>
STP is the condition at which the temperature and the pressure of the gas are at the normal and standard conditions.
The density of the ammonia = 681.9gm/L
The mass = 4084 gm
The volume is calculated as:
V = Mass ÷ Volume
= 4084 ÷ 681.9
= 5.99 L
Therefore, at STP the volume of ammonia is 5.99 L.
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Answer:
Never store used oil in anything other than tanks and storage containers. Used oil may also be stored in units that are permitted to store regulated hazardous waste. Tanks and containers storing used oil do not need to be RCRA permitted, however, as long as they are labeled and in good condition.
This uses the concept of freezing point depression. When faced with this issue, we use the following equation:
ΔT = i·Kf·m
which translates in english to:
Change in freezing point = vant hoff factor * molal freezing point depression constant * molality of solution
Because the freezing point depression is a colligative property, it does not depend on the identity of the molecules, just the number of them.
Now, we know that molality will be constant, and Kf will be constant, so our only unknown is "i", or the van't hoff factor.
The van't hoff factor is the number of atoms that dissociate from each individual molecule. The higher the van't hoff factor, the more depressed the freezing point will be.
NaCl will dissociate into Na+ and Cl-, so it has i = 2
CaCl2 will dissociate into Ca2+ and 2 Cl-, so it has i = 3
AlBr3 will dissociate into Al3+ and 3 Br-, so it has i = 4
Therefore, AlBr3 will lower the freezing point of water the most.
<span>The sun and planets formed from a collapsing spinning cloud of gas and dust.</span>
Late answer:
Chromosphere.
