Answer:
4.34x10⁻¹⁹ J
Explanation:
The total energy emitted by irradiation is given by
E = hf, where E is the energy, <em>h</em> is the plack constant (6.626x10⁻³⁴ J.s), and <em>f</em> is the frequency. The frequency is also the velocity of the light (c = 2.99x10⁸ m/s) divided by the length of the irradiation (254x10⁻⁹ m). So:
E = (6.626x10⁻³⁴)x(2.99x10⁸)/ (254x10⁻⁹)
E = 7.80x10⁻¹⁹ J
The energy to remove 1 electron is the energy necessary to remove 1 mol divided by the Avogadros number ( 1 mol = 6.02x10²³ electrons):
208400/6.022x10^23 = 3.46x10⁻¹⁹ J
The total energy is the energy necessary to remove one electrons plus the kinectic energy (Ek) of the electrons:
7.80x10⁻¹⁹ = 3.46x10⁻¹⁹ + Ek
Ek = 7.80x10⁻¹⁹ - 3.46x10⁻¹⁹
Ek = 4.34x10⁻¹⁹ J
Dsm-5 includes gambling disorder as an addictive disorder, along with substance use disorders. This change is considered important because it suggest that people may become addicted to behavior net just substance.
<h3>What is Gambling ? </h3>
Gambling disorder which involve repeated, problem gambling behavior. The behavior leads to problem for the individual families, and society.
The emotional and physical sign of gambling disorder are:
- Anxiousness and Depression
- Hopelessness
- Lack of sleep
- Pallor to skin
- Gain loss of weight
<h3>What are the effects of gambling disorder ?</h3>
Gambling disorder make another kind of addiction that an individual uses to be able to deal with the situation. Start using the drugs alcohol to reduce the feeling of anxiety.
Thus from the above conclusion we can say that Dsm-5 includes gambling disorder as an addictive disorder, along with substance use disorders. This change is considered important because it suggest that people may become addicted to behavior net just substance.
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The balanced half-reaction for the product that forms at anode is Fe⁺² + 2e⁻ → Fe(s) and 2H₂O + 2e⁻ → H₂ + 2OH⁻, the product that forms at cathode is 2I⁻ → I₂ + 2e- and 2H₂O → O₂ + 4H⁺ + 4e⁻
<h3>What is Balanced Chemical Equation ?</h3>
The equation during which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation is called balanced chemical equation.
Now write the equation for FeI₂
At cathode:
Fe⁺² + 2e⁻ → Fe(s) Eo = - 0.44 V
2H₂O + 2e⁻ → H₂ + 2OH⁻ Eo = - 0.827 V
It is easy to decrease Fe⁺² ions than the water, the product which is formed at cathode is Iron.
At anode:
2I⁻ → I₂ + 2e- Eo = - 0.54 V
2H₂O → O₂ + 4H⁺ + 4e⁻ Eo = -1.23 V
O₂ gas formed at anode.
Thus from the above conclusion we can say that The balanced half-reaction for the product at anode is Fe⁺² + 2e⁻ → Fe(s) and 2H₂O + 2e⁻ → H₂ + 2OH⁻, the product that forms at cathode is 2I⁻ → I₂ + 2e- and 2H₂O → O₂ + 4H⁺ + 4e⁻.
Learn more about the Balanced chemical equation here: brainly.com/question/26694427
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Answer:
Amylase.
Explanation:
The process of digestion begin to start in mouth when food mix with saliva. An enzyme is released which is called Amylase help in digestion of carbohydrates.