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Ilia_Sergeevich [38]
3 years ago
14

Fdsddddgdgdgdgsdggd.

Chemistry
1 answer:
larisa [96]3 years ago
4 0
Fdsddadgdsadgsd:
Fasdadasdfadsdfasdf asfsadafasdfasdffdaddad dads fdfgdfgfdg

Fdgdfgdfgdgfggggfg gdfgdfgd:
Fgdfgdfgdfgrdfhdf hdfgdfhdfh == fhdfgdfh /fhdgdg .
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Which of the following is not a characteristic of metals? A. good conductors B. ductile and malleable C. incompressible D. cryst
Maru [420]
A. good conductors is not a characteristic of metals out of all the other followings.
4 0
4 years ago
Read 2 more answers
Show work
Anna11 [10]

Answer:

7 =  2.3× 10⁺⁹ mm

8 = The density of copper is 6.55g/cm³ so the given metal is not copper.

9 = mass of liquid is 7.8 g

10 = mass of liquid is 8050 g.

Explanation:

7. How many mm are there in 2.3Mm?

mm is the symbol of millimeter.

Mm is the symbol of megameter.

1 mm = 10⁻⁹Mm

so in order to convert 2.3Mm into mm we will multiply the given value with 10⁺⁹

2.3 mm × 10⁺⁹ = 2.3× 10⁺⁹ mm

8. Copper has a density of 6.55g/cmº. A. piece of metal has a mass of 48.3g and a volume of 7.2cm.

Is this metal copper?

Given data:

Density of copper = 6.55 g/cm³

Mass of metal = 48.3 g

Volume of metal = 7.2 cm³

Is the metal is copper = ?

Solution:

The given problem will be solved through the density formula.

D = m/v

We will put the values in formula to calculate the density.

d = 48.3 g/ 7.2 cm³

d = 6.71 g/cm³

The density of copper is 6.55g/cm³ so the given metal is not copper.

9. What is the mass of a liquid whose volume is 6.0 mL and a density of 1.3 g/cm??

Given data:

Volume of liquid = 6.0 mL (1 mL = 1cm³)

Density of liquid = 1.3 g/cm³

Mass of liquid = ?

Solution:

Formula:

D = m/v

By putting the values in formula.

1.3 g/cm³ = m / 6 cm³

m =  1.3 g/cm³ × 6 cm³

m = 7.8 g

mass of liquid is 7.8 g.

10. You have 3.50 L of a liquid, whose density is 2.3g/cm3. What is it's Mass?

Given data:

Volume of liquid = 3.50L (3.50 ×1000 = 3500 cm³)

Density of liquid = 2.3g/cm³

Mass of liquid = ?

Solution:

Formula:

D = m/v

By putting the values in formula.

2.3g/cm³ = m /3500cm³

m = 2.3 g/cm³ × 3500 cm³

m = 8050 g

mass of liquid is 8050g.

7 0
3 years ago
Does water evaporates only from the sea
svetlana [45]

Answer:

false

Explanation:

6 0
3 years ago
Read 2 more answers
Do Alkali Metal Compounds form precipitates? And Why?
Alexeev081 [22]

Answer:

Alkali metal hydroxides can be used to test the identity of metals in certain salts. The colour of the precipitate will help identify the metal : Calcium hydroxide is soluble; no precipitate is formed.

6 0
3 years ago
How many grams of solid Na2CO3 are required to neutralize exactly 2 liters of an HCI solution of pH 2.0?
Snezhnost [94]

Answer:

The answer is 1.06g.

Explanation:

Analysis of question:

1. Identify the information in the question given.

  • volume of HCl is 2 dm3
  • pH of HCl is 2.0

2. What the question want?

  • mass of Na2CO3 is ?(unknown)
  • 3. Do calculation.
  • 1st-Write a balanced chemical equation:

Na2CO3 + 2HCl (arrow) 2NaCl + H20 + CO2

  • 2nd-Determine the molarity of HCl with the value of 2.0.

pH= -log[H+]

2.0= -log[H+]

log[H+]= -2.0

[H+]= 10 to the power of negative 2(10-2)

=0.01 mol dm-3

molarity of HCl is 0.01 mol dm-3

  • 3rd-Find the number of moles of HCl

n=MV

=0.01 mol dm-3 × 2 dm3

=0.02 mol of HCl

  • 4th-Find the second mol of it.

Based on the chemical equation,

2.0 mol of HCl reacts with 1.0 mol of Na2CO3

0.02 mol of HCl reacts with 0.01 mol of Na2CO3

<u>N</u><u>a</u>2CO3>a=<u>1</u><u> </u>mol

<u>2</u><u>H</u>Cl>b=<u>2</u><u> </u>mol

  • 5th-Find the mass of it.

mass= number of mole × molar mass

g=0.01 × [2(23)+ 12+ 3(16)]

g=0.01 × 106

# =1.06 g.

3 0
3 years ago
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