Answer:
B, H, E, G, C, D, A, F
Explanation:
The ones closest to the bottom are the oldest
The ecosystem services provided by the each of the given examples are as follows:
- A cornfield in Kansas provides provisioning services.
- Bacteria that decompose waste along the Gulf Coast provides regulating services.
- Ocean currents that keep Pacific Northwest air cool and moist provides regulating services.
- Flower garden at a national landmark provides cultural services.
- Lumber from an oak tree provides provisioning services.
- Animals that eat seeds and then spread the seeds through their waste regulating services.
<h3>Ecosystem services</h3>
Ecosystem services are defined as the benefits derived by man from the surroundings ecosystems.
<h3>Categories of ecosystem services</h3>
The four categories of ecosystem services are:
- regulating services,
- provisioning services,
- cultural services, and
- supporting services
A cornfield in Kansas provides provisioning services.
Bacteria that decompose waste along the Gulf Coast provides regulating services.
Ocean currents that keep Pacific Northwest air cool and moist provides regulating services.
Flower garden at a national landmark provides cultural services.
Lumber from an oak tree provides provisioning services.
Animals that eat seeds and then spread the seeds through their waste regulating services.
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Answer:
it becomes a negstive charge
Answer:
Molarity = 0.3 M
Explanation:
Given data:
Moles of NaOH = 0.720 mol
Volume of water = 2.40 L
Molarity = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Molarity = 0.720 mol / 2.40 L
Molarity = 0.3 mol/L
Molarity = 0.3 M
If the gases are at the same temperature and pressure, the ratio of their effusion rates is directly proportional to the ratio of the square roots of their molar masses:
<h3>Graham's law of diffusion </h3>
This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e
R ∝ 1/ √M
R₁/R₂ = √(M₂/M₁)
Where
- R₁ and R₂ are the rates of the two gas
- M₁ and M₂ are the molar masses of the two gas
From the Graham's law equation, we can see that the ratio of the rates of effusion of the two gases is directly proportional to the square root of their molar masses
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