Answer:
See explanation and image attached
Explanation:
Alkenes undergo hydrogenation to give the corresponding alkanes. Where the structure of the original alkene is unknown, we can deduce the structure of the alkene from the structure of the products obtained when it undergoes various chemical reactions.
Now, the fact that we obtained 2-methylhexane upon hydrogenation and the two compounds had different heats of hydrogenation means that the two compounds were geometric isomers. The original compounds must have been cis-2-methyl-3-hexene and trans-2-methyl-3-hexene.
When reacted with HCl, the same compound C7H15Cl is formed because the stereo chemistry is removed.
However, we know that the trans isomer is more stable than the cis isomer hence the cis isomer always has a higher heat of hydrogenation than the trans isomer. Thus X is cis-2-methyl-3-hexene.
Answer:
Option A) Na
Explanation:
From the options given above, sodium (Na) is most likely to lose electron to form ion
Na is a group 1 metal. Metals form ions by losing electron(s).
From the options given above, only Na is a metal and so it is most likely to form ion by losing electron
Answer:
Barium and Chlorine
Explanation:
Ionic bonds are formed between metals and non metals where the metals lose electrons and become positively charged and the non metals gain electrons and become negatively charge. The opposite charges cause them to be attracted to each other and Bond. The only metal in those options above is Barium. Therefore an ionic bond will be formed between Barium and Chlorine.
Answer:
The number of moles of the chemical constituents will be less than the actual amount.
Explanation:
In calculating empirical formula, we begin with the number of grams of each element, given in the problem.
Given that the spill will affect the mass concentration of the copper chloride solution, calculations to determine the molecular formula (using Molarity = mass conc ÷ molecular mass ) would give a lesser result, which would in turn lower the number of moles of the copper and chloride in the empirical formula calculation.
Answer:
the reducing flame also called the carburizing flame.
Explanation:
because it gets the oxides of the unknown salts
