Question

23g of sodium reacted with 35.5g of chlorine. Calculate the mass of the sodium chloride compound formed.

Answer 1

58.5 is the final mass of the compound as long as any gases the reaction causes to be

Answer 2

Answer: The mass of sodium chloride formed will be 58.5 g

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$     .....(1)

• For Sodium:

Given mass of sodium = 23 g

Molar mass of sodium = 23 g/mol

Putting values in equation 1, we get:

$\text{Moles of sodium}=\frac{23g}{23g/mol}=1mol$

• For chlorine gas:

Given mass of chlorine gas = 35.5 g

Molar mass of chlorine gas = 71 g/mol

Putting values in equation 1, we get:

$\text{Moles of chlorine gas}=\frac{35.5g}{71g/mol}=0.5mol$

The chemical reaction for the formation of sodium chloride follows the equation:

$2Na+Cl_2\rightarrow 2NaCl$

By stoichiometry of the reaction:

2 moles of sodium reacts with 1 mole of chlorine gas.

So, 1 mole of sodium will react with = $\frac{1}{2}\times 1=0.5mol$ of chlorine gas.

Thus, the formation of sodium chloride can be calculated by using any of the reactant.

By stoichiometry of the reaction:

2 moles of sodium produces 2 moles of sodium chloride.

So, 1 mole of sodium will react with = $\frac{2}{2}\times 1=1mol$ of sodium chloride.

Now, calculating the mass of sodium chloride by using equation 1, we get:

Moles of sodium chloride = 1 mole

Molar mass of sodium chloride = 58.5 g/mol

Putting values in equation 1, we get:

$1mol=\frac{\text{Mass of NaCl}}{58.5g/mol}\\\\\text{Mass of NaCl}=58.5g$

Hence, the mass of sodium chloride formed will be 58.5 g