All categories

2 years ago

8÷7/9 (urgent) plzzz I need this

Mathematics

2 answers:

lubasha [3.4K]2 years ago

8 0

10 2/7 or 10.285714 why dont you just use a calculator?

8090 [49]2 years ago

4 0

Answer:

72/7

Step-by-step explanation:

Reduce the expression, if possible, by cancelling the common factors

You might be interested in

Express 0.008 in value words

enot [183]

0.008 = eight thousandths

Hope it helps

6 0

3 years ago

Read 2 more answers

What is the formula for the expected number of successes in a binomial experiment with n trials and probability of success p? C

charle [14.2K]

Answer:

$(D)E[ X ] =np.$

Step-by-step explanation:

Given a binomial experiment with n trials and probability of success p,

$f(x)=\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}, 0\leq x\leq n$

$E(X)=\sum_{x=0}^{n}xf(x)= \sum_{x=0}^{n}x\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}$

Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:

$E(X)=\sum_{x=1}^{n}x\left(\begin{array}{c}n\\x\end{array}\right)p^x(1-p)^{n-x}$

Now,

$x\left(\begin{array}{c}n\\x\end{array}\right)= \frac{xn!}{x!(n-x)!}=\frac{n!}{(x-)!(n-x)!}=\frac{n(n-1)!}{(x-1)!((n-1)-(x-1))!}=n\left(\begin{array}{c}n-1\\x-1\end{array}\right)$

Substituting,

$E(X)=\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^x(1-p)^{n-x}$

Factoring out the n and one p from the above expression:

$E(X)=np\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^{x-1}(1-p)^{(n-1)-(x-1)}$

Representing k=x-1 in the above gives us:

$E(X)=np\sum_{k=0}^{n}n\left(\begin{array}{c}n-1\\k\end{array}\right)p^{k}(1-p)^{(n-1)-k}$

This can then be written by the Binomial Formula as:

$E[ X ] = (np) (p +(1 - p))^{n -1 }= np.$

5 0

3 years ago

Find the sum of 46 + 42 + 38 + ... + (-446) + (-450)46+42+38+...+(−446)+(−450)

JulijaS [17]

sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

<u>Step-by-step explanation:</u>

We need to find sum of sequence : 46 + 42 + 38 + ... + (-446) + (-450)

Given sequence is an AP with following parameters as :

$a=46\\d=42-46=-4$

So , Let's calculate how many terms are there as :

⇒ $a_n=a +(n-1)d$

⇒ $-450=46 +(n-1)(-4)$

⇒ $-496=(n-1)(-4)$

⇒ $\frac{-496}{-4}=n-1$

⇒ $124=n-1$

⇒ $n=125$

Sum of an AP is :

⇒ $S_n = \frac{n}{2}(2a+(n-1)d)$

⇒ $S_1_2_5 = \frac{125}{2}(2(46)+(125-1)(-4))$

⇒ $S_1_2_5 = \frac{125}{2}(-404)$

⇒ $S_1_2_5 =-25,250$

Therefore , sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

3 0

3 years ago

Read 2 more answers

When Camden runs the 400 meter dash, his finishing times are normally distributed with a mean of 65 seconds and a standard devia

Keith_Richards [23]

Answer:

63.5, 66.5

Step-by-step explanation:

7 0

3 years ago

The camp director is putting 85 sack lunches in boxes for a picnic. She can fit 8 lunches in each box. She does the division pro

Tom [10]

Answer:

Step-by-step explanation:

Because that’s the answer Lol

4 0

3 years ago

8÷7/9 (urgent) plzzz I need this​

8÷7/9 (urgent) plzzz I need this