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3 years ago

Write two examples of machine which increases the speed of doing work

Physics

2 answers:

julia-pushkina [17]3 years ago

6 0

Answer:

Explanation:

Speed multipliers are useful when an object needs to move a further distance or at a higher speed. Some examples are wheels and axles and third class levers. Machines can be either simple or complex. Simple machines are machines that only use one type of machine, such as a lever or an inclined plane.

Schach [20]3 years ago

6 0

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A freight train rolls along a track with considerable momentum. If it were to roll at the same speed but had twice as much mass,

fomenos

Answer:

The momentum would be doubled

Explanation:

The magnitude of the momentum of the freight train is given by:

$p=mv$

where

m is the mass of the train

v is its speed

In this problem, we have that the speed of the train is unchanged, while the mass of the train is doubled:

$m'=2m$

therefore, the new momentum is

$p'=m'v=(2m)v=2(mv)=2p$

so, the momentum has also doubled.

7 0

3 years ago

The current in two identical light bulbs connected in series is 0. 25 A. The voltage across both bulbs is 110 V. The resistance

konstantin123 [22]

Answer:

220 ohms

Explanation:

I = V / R

0.25 = 110 / R

R = 110 / 0.25

R = 440 ohms

Equivalent resistance = 440 ohms

Resistance of single light bulb = Equivalent resistance / number of bulbs

= 440 / 2

= 220 ohms

8 0

2 years ago

A passenger train travels 392 mi in the same time that it takes a freight train to travel 322 mi. If the passenger train travels

Yuri [45]

Answer:

Explanation:

Given

distance traveled by Passenger train is $d_1=392\ mi$

distance traveled by Freight train is $d_2=322\ mi$

Both take same time to travel

suppose speed of freight train is x mph

so speed of passenger train is 20+x mph

we know time $=\frac{distance}{speed}$

$t=\frac{392}{20+x}=\frac{322}{x}$

$392x=322x+322\times 20$

$70x=322\times 20$

$x=92\ mph$

speed of passenger train $x+20=112\ mph$

6 0

3 years ago

A horse shoe magnet is placed on a mass balance such that a uniform magnetic field of magnitude B runs between it from North to

BARSIC [14]

Answer:

(a) Measured change in mass (Δm) = BVL/Rg

(b) Total measured mass M' = M - BVL/Rg

Explanation:

Current (I) across is coil is given by the formula;

I = V/R ------------------------1

The magnetic force is given by the formula;

Fb = B*I*L -------------------2

Putting equation 1 into equation 2, we have;

Fb = B*V*L/R -------------------3

Change in mass (Δm) is given as:

Δm = Fb/g -----------------------4

Putting equation 3 into equation 4, we have;

Δm = BVL/Rg

Therefore, change in mass (Δm) = BVL/Rg

2. Since B runs from North to South and current running from East to West, then the magnetic force is directed upward.

Therefore,

Total measure mass M' = M - BVL/Rg

4 0

3 years ago

Suppose you exert a 400-N force on a wall but the wall does not move. The work you are doing on the wall is : unknown, because t

Ilya [14]

Answer:

W = 0 :The work done on the wall is zero,because the wall is not moving

Explanation:

Work theory

Work is the product of a force applied to a body and the displacement of the body in the direction of this force.

W= F*d Formula (1)

W: Work (Joules) (J)

F: force applied (N)

d=displacement of the body (m)

The work is positive (W+) if the force goes in the same direction of movement.

The work is negative (W-)if the force goes in the opposite direction to the movement

Data

F= 400-N

d= 0

Problem development

We apply formula (1) to calculate the work done on the wall:

W= 400*0

W=0

6 0

3 years ago

Write two examples of machine which increases the speed of doing work​

Write two examples of machine which increases the speed of doing work