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lord [1]
3 years ago
7

HIIIIIIIIIIIIIIIIIII WHAT IS 50X550

Physics
1 answer:
jekas [21]3 years ago
3 0
50 x 550 is 27500!!!!
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A coaxial cable carries a current I =0.02A through a wire of radius Rw=.2mmin one direction and an identical current through the
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Answer:

a)  B = 10⁻¹ r , b)  B = 4 10⁻⁹ / r , c) B=0

Explanation:

For this exercise let's use Ampere's law

            ∫ B. ds = μ₀ I

Where I is the current locked in the path. Let's take a closed path as a circle

          ds = 2π dr

          B 2π r = μ₀ I

          B = μ₀ I / 2μ₀ r

Let's analyze several cases

a) r <Rw

Since the radius of the circumference is less than that of the wire, the current is less, let's use the concept of current density

          j = I / A

For this case

         j = I /π Rw² = I’/π r²

         I’= I r² / Rw²

The magnetic field is

        B = (μ₀/ 2π) r²/Rw²   1 / r

        B = (μ₀ / 2π) r / Rw²

calculate

        B = 4π 10⁻⁷ /2π   r / 0.002²

        B = 10⁻¹ r

b) in field  between   Rw <r <Rs

In this case the current enclosed in the total current

      I = 0.02 A

      B = μ₀/ 2π   I / r

      B = 4π 10⁻⁷ / 2π  0.02 / r

      B = 4 10⁻⁹ / r

c) the field outside the coaxial Rs <r

In this case the waxed current is zero, so

       B = 0

7 0
3 years ago
The mass number of iodine is 126, and it’s in the 53rd place in the periodic table. It has
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It has 52 Protons and 73 Neutrons
7 0
3 years ago
Hydroelectric power plants can generate huge amounts of electricity. Which of these statements best describes the impact of a hy
Zarrin [17]
The best answer is that it reduces the level of ground water
7 0
3 years ago
Read 2 more answers
A gas-turbine power plant operates on the simple Brayton cycle between the pressure limits of 100 and 1600 kPa. The working flui
anzhelika [568]

Answer:

a) 6498.84 kW

b) 0.51

c) 0.379

Explanation:

See the attached picture below for the solution

7 0
3 years ago
When I wave a charged golf tube at the front of the classroom with a frequency of two oscillations per second, I produce an elec
borishaifa [10]

To solve the exercise it is necessary to take into account the concepts of wavelength as a function of speed.

From the definition we know that the wavelength is described under the equation,

\lambda = \frac{c}{f}

Where,

c = Speed of light (vacuum)

f = frequency

Our values are,

f = 2Hz

c = 3*10^8km/s

Replacing we have,

\lambda = \frac{c}{f}

\lambda = \frac{3*10^8km/s}{2Hz}

\lambda = 1.5*10^8m

<em>Therefore the wavelength of this wave is 1.5*10^{8}m</em>

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