Which of the following describes a chemical reaction?

1 answer:

4 0

I think the correct answer from the choices listed above is option B. Atoms in substances react with each other describes a chemical reaction. From the statement itself, the word react is present this signifies a reaction. Hope this answers the question.

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In the following list, only is not an example of a chemical reaction

Sladkaya [172]

There is no pictu-res...sss

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2 years ago

Which greenhouse gas is emitted when people burn fossil fuels for energy?

Volgvan

It would be carbon dioxide because carbon dioxide makes up the vast majority of greenhouse gas .

5 0

3 years ago

Can someone please give me a simple equation on the mass of an isotope

frutty [35]

Mass 1 + %abundance of first isotope + Mass 2 + %abundance of second isotope
/ 100
This is RAM.

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2 years ago

A CaCl2 solution is given to increase blood levels of calcium. If a patient receives 6.1 mL of a 12 % (m/v) CaCl2 solution, how

Yuliya22 [10]

Mass of CaCl₂ = 0.732 g

<h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

$\tt \%(m/v)\rightarrow 12\%=\dfrac{mass~CaCl_2}{volume~of~solution}\times 100\%\\\\mass~CaCl_2=12\%\times 6.1\div 100\%\\\\mass~CaCl_2=0.732~g$

5 0

3 years ago

If 25.5g of sodium thiosulphate was dissolved in 40g of distilled water at 25°C,

zhenek [66]

Answer:

Formula: Na2S2O3

we get solubility.

Divide the mass of the compound by the mass of the solvent and then multiply by 100 g to calculate the solubility in g/100g .

Solution given:

mass of sodium thiosulphate [m1]=25.5g

mass of water [m2]=40g

at temperature [t]=25°C

we have

solubility in g/dm^3 : $\frac{solute in gram}{solvent in gram} *100$

= $\frac{25.5}{40}*100$
=63.75g /litre=63.75g/dm³

solubility in g/dm^3 :63.75g/dm³

now

solubility of the solute in mol/dm^3=:63.75g/dm³/178=0.4 mol/dm³

6 0

2 years ago