<span>2CH</span>₃<span>OH + 3O</span>₂<span> → 2CO</span>₂ + <span> 4H</span>₂O
mole ratio of CO₂ : H₂O is 2 : 4 (simplified as 1 : 2)
∴ if moles of CO₂ = 3.25 moles
then moles of H₂O = 3.25 moles × 2
= 6.50 moles
4- KOH
KOH is a strong base. In water it dissociates as
<span>KOH--> K+ + OH- </span>
<span>A is acetic acid, a weak acid </span>
<span>CH3OH is an alcohol, weakly acidic in water </span>
<span>HCl is a strong acid.</span>
It's answer B) endothermic reaction ;)
Answer:
it can be revised at any time.
Explanation:
Answer:
pH = 8.48
Explanation:
HOBr dissociates in water as follows:
- HOBr(aq) ↔ H⁺(aq) + OBr⁻(aq)
With a ka expressed by:
- ka = [H⁺]*[OBr⁻] / [HOBr]
We rearrange and <u>solve for [H⁺]</u>:
- [H⁺] = ka * [HOBr] / [OBr]
Because the volume is 1 L, the moles added of HOBr and KOBr (OBr⁻) are also the molar concentration:
- [H⁺] = 2.0x10⁻⁹ * 0.50 / 0.30
Finally we <u>calculate the pH</u>: