This is due to the hydroxyl group in the alcohol which is able to form hydrogen bonds with water molecules.
Answer:
146 mL
Explanation:
Step 1: Write the balanced equation
H₃PO₄ + 3 NaOH ⇒ Na₃PO₄ + 3 H₂O
Step 2: Calculate the reacting moles of sodium hydroxide
119 mL of 0.315 M NaOH react.
Step 3: Calculate the reacting moles of phosphoric acid
The molar ratio of H₃PO₄ to NaOH is 1:3. The reacting moles of H₃PO₄ are 1/3 × 0.0375 mol = 0.0125 mol.
Step 4: Calculate the reacting volume of phosphoric acid
0.0125 moles of H₃PO₄ are in a 0.0855 M solution.
Answer:
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Answer: V2= 41.2mL
Explanation:
Givens:
* V1= 20ml
* T1 = -109 ⁰C --> K= ⁰C + 273.15 --> 164.15 K
* V2 = ??
* T2= 338.15 K
Use Charles law V1/T1 = V2/T2
Since we are looking for V2 we can rearrange the formula to
V2= (T2 x V1) /T1
V2= (338.15K x 20mL) / 164.15 K
V2= 41.2mL
NOTE:
Temperature should always be in K not in ⁰C or ⁰F
To convert from C to K use
*K= ⁰C + 273.15
Enter your C value in the ( ⁰C ) and you can get K
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