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Alex17521 [72]
2 years ago
6

8x=12+12Find the value of x​.​

Mathematics
2 answers:
MakcuM [25]2 years ago
6 0

Answer:

<h2>x = 23</h2>

Step-by-step explanation:

<h3>= > 8x = 12 + 12</h3><h3>= > 8x = 24</h3><h3>= > x = 24/8</h3><h3>= > x = 3...ans </h3>

<h2>HOPE IT HELPS YOU!! </h2>
djverab [1.8K]2 years ago
5 0

Answer:

\sf\longmapsto \: x = 3

Step-by-step explanation:

\sf\longmapsto \: 8x = 24

\sf\longmapsto \: x =  \frac{24}{8}

\sf\longmapsto \: x = 3

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0ut of 30 litres of milk, bought for rs 15.50 per litre ,4 litres are lost by leakage. what is gained by selling the remainder a
Fudgin [204]

Answer:

55 Rs.

Step-by-step explanation:

cost of the milk:

15.5 x 30 = 465 Rs.

Gross sales of the milk:

26 x 20 = 520 Rs.

Profit:

520 - 465 = 55 Rs.

4 0
3 years ago
rita bought 5 pairs of sock.each pair cost $ 4.how much did rita spend on socks.explain how you know​
Alla [95]
Rita spent 20$. By multiplying 5 pairs with 4$ we can see that it will equal 20$
8 0
3 years ago
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The quotient of 300 and the quality of x times 2
asambeis [7]
\frac{300}{ x^{2}} 
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3 years ago
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Use sigma notation to represent the sum of the first seven terms of the following sequence -4,-6,-8.....
lina2011 [118]

Answer:Answer:

\sum\left {{7} \atop {1}} \right -n(3+n)

Step-by-step explanation:

Given the sequence -4,-6,-8..., in order to get sigma notation to represent the sum of the first seven terms of the sequence, we need to first calculate the sum of the first seven terms of the sequence as shown;

The sum of an arithmetic series is expressed as S_n = \frac{n}{2}[2a+(n-1)d]

n is the number of terms

a is the first term of the sequence

d is the common difference

Given parameters

n = 7, a = -4 and d = -6-(-4) = -8-(-6) = -2

Required

Sum of the first seven terms of the sequence

S_7 = \frac{7}{2}[2(-4)+(7-1)(-2)]\\\\S_7 =  \frac{7}{2}[-8+(6)(-2)]\\\\S_7 =  \frac{7}{2}[-8-12]\\\\\\S_7 = \frac{7}{2} * -20\\\\S_7 = -70

The sum of the nth term of the sequence will be;

S_n = \frac{n}{2}[2(-4)+(n-1)(-2)]\\\\S_n = \frac{n}{2}[-8+(-2n+2)]\\\\S_n = \frac{n}{2}[-6-2n]\\\\S_n =  \frac{-6n}{2} -  \frac{2n^2}{2}\\S_n = -3n-n^2\\\\S_n = -n(3+n)

The sigma notation will be expressed as \sum\left {{7} \atop {1}} \right -n(3+n). <em>The limit ranges from 1 to 7 since we are to  find  the sum of the first seven terms of the series.</em>

3 0
3 years ago
-2 =5 - 7x how do you do this
Paul [167]
First you want to get x by it’s self so you need to get ride of your 5 so you subtract 5 on both sides leaving you with -2 and -5 on the same side then you combine those two number to get -7 now to get your x all you have to do is divide both sides by -7 since your x is -7 once once your x is now by its self but on the other side -7 divided by -7 equals 1 bc 7 goes into 7 once and it turns positive because anytime you divide an negative number by a negative number it turns into a positive number so your answer over all is 1=x
6 0
2 years ago
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