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Zigmanuir [339]
3 years ago
15

What is the pH of a solution with a concentration of 2.4 × 10-5 molar H3O+? Show, or explain, the work used to solve this proble

m.
Chemistry
2 answers:
MrRissso [65]3 years ago
7 0
pH=-log|H_{3}O^{+}|\\\\
pH=-log2.4*10^{-5}=-(log2.4+log10^{-5})=-(0,38-5)=-(-4.62)\\\\
pH=4.62
Rina8888 [55]3 years ago
4 0

Answer:

The pH of the solution is 4.61.

Explanation:

The pH of the solution is defined as negative logarithm of H_3O^+ ion concentration.

pH=-\log[H_3O^+]

The concentration of H_3O^+=2.4\times 10^{-5} molar

pH=-\log[2.4\times 10^{-5} M]=4.61

The pH of the solution is 4.61.

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if 0.953 g of copper was actually recovered at the end of the entire experiment, what would be the percent yield?
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Here is the full question:

Cu(s) + 4HNO3(aq) -> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l)

1.000 g copper wire is reacted with 10 mL of concentrated nitric acid (16M). If 0.953 g of copper was actually recovered at the end of the entire experiment, what would be the percent yield?

Answer:

95.30 %

Explanation:

equation for the reaction is given as:

Cu(s) + 4HNO3(aq) -> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l)

1.00 g of Cu = \frac{1.00}{63.54 mol of Cu}

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