Answer:
D. Convert the 0.2 kg of NaCl to moles of NaCl
Explanation:
The molality equation looks like this:
Molality = moles of solute / mass (kg) of solvent
In this case, the solute is NaCl and the solution is water. So, if you have been given NaCl in kg, you need to convert it to grams and then to moles in order to plug it into the equation.
Formula for Barium Nitrate = Ba(NO3)2
Thus based on stoichiometry:
1 mole of Ba(NO3)2 contains 2 moles of NO3-
Therefore, concentration of nitrate ion NO3- would be = 2*0.240 = 0.480 M
Use the relation:
V1M1 = V2M2
V1 = V2M2/M1 = 0.500 L * 0.0800/0.480 = 0.0833 L
Thus, 0.0833 L or 83.3 ml solution of Ba(NO3)2 would be required.
Answer:
The answer is
<h2>0.15 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question
mass of object = 13.57 g
volume = 89.6 mL
The density is
We have the final answer as
<h3>0.15 g/mL</h3>
Hope this helps you
