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andreev551 [17]
2 years ago
9

Describe the properties of alkaline earth metals. Based on their electronic arrangement, explain whether they can exist alone in

nature. (8 points)
Chemistry
2 answers:
zheka24 [161]2 years ago
7 0

Answer: all i know about alkaline metals is he alkaline earth metals are shiny, silvery-white, and somewhat reactive metals at standard temperature and pressure.

All the alkaline earth metals readily lose their two outermost electrons to form cations with a 2+ charge.

All of the alkaline earth metals except magnesium and strontium have at least one naturally occurring radioisotope.

Magnesium and calcium are ubiquitous and essential to all known living organisms.

Explanation:

pantera1 [17]2 years ago
4 0
No egdhddh dhfhf dudar he e have eje e she fvdrjdvdr th
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Bradley was working in the lab. He accidentally poured a container of concentrated hydrochloric acid into his container of disti
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Answer is: The solution has now become a good conductor of electricity.

Hydrochloric acid (HCl) dissociate on positive ions or cations of hydogen (H⁺) and negative ions or anions of chlorine (Cl⁻) accordinf to balanced chemical reaction:

HCl(aq) → H⁺(aq) + Cl⁻(aq).

When there are free cations and ions, water solution can conduct electricity.

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If you have a solution that contains 46.85 g of codeine, C18H21NO3, in 125.5 g of ethanol, C2H5OH, what is the mole fraction of
irakobra [83]

Answer:

0.22

Explanation:

Given, Mass of C_{18}H_{21}NO_3 = 46.85 g

Molar mass of C_{18}H_{21}NO_3 = 299.4 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{46.85\ g}{299.4\ g/mol}

Moles\ of\ C_{18}H_{21}NO_3= 0.1565\ mol

Given, Mass of C_{2}H_{5}OH = 125.5 g

Molar mass of C_{2}H_{5}OH = 46.07 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{125.5\ g}{46.07\ g/mol}

Moles\ of\ C_{2}H_{5}OH= 0.5535\ mol

So, according to definition of mole fraction:

Mole\ fraction\ of\ codeine=\frac {n_{codeine}}{n_{codeine}+n_{ethanol}}

Mole\ fraction\ of\ codeine=\frac{0.1565}{0.1565+0.5535}=0.22

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3 years ago
How many protons does the neutral atom pictured have?<br> A) 8<br> B) 18<br> C) 2<br> D) 20
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Answer:

b 18

Explanation:

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Name two compounds in unpolluted air?
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Nitrogen and oxygen are in unpolluted air

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