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tester [92]
3 years ago
8

As you have seen, ozone is formed in the upper atmosphere through the reaction:

Chemistry
1 answer:
baherus [9]3 years ago
5 0

The rate law equation for Ozone reaction

r=k[O][O₂]

<h3>Further explanation</h3>

Given

Reaction of Ozone :.

O(g) + O2(g) → O3(g)

Required

the rate law equation

Solution

The rate law is a chemical equation that shows the relationship between reaction rate and the concentration / pressure of the reactants

For reaction

aA + bB ⇒ C + D

The rate law can be formulated:

\large{\boxed{\boxed{\bold{r~=~k.[A]^a[B]^b}}}

where

r = reaction rate, M / s

k = constant, mol¹⁻⁽ᵃ⁺ᵇ⁾. L⁽ᵃ⁺ᵇ⁾⁻¹. S⁻¹

a = reaction order to A

b = reaction order to B

[A] = [B] = concentration of substances

So for Ozone reaction, the rate law (first orde for both O and O₂) :

\tt \boxed{\bold{r=k[O][O_2]}}

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A. monotomic ionic
ASHA 777 [7]

Answer:

Binary compound

Explanation:

Binary compounds:

The compounds which are made up of the atoms of only two elements are called binary compounds.

For example:

The following compounds are binary:

HCl

H₂O

NH₃

HCl is binary because it is composed of only hydrogen and chlorine. Ammonia is also binary compound because it is made up of only two elements nitrogen and hydrogen.

water is also binary because it is also made up of only two elements hydrogen and oxygen.

SF₆ is binary compound because it consist of atoms of only two elements i.e, sulfur and fluorine.

7 0
3 years ago
The lab just ran out of 1 M HCl that you need to complete the Benzillic Acid lab. The TA tells you there is 12 M HCl in the fume
Viktor [21]

Answer:

0.83 mL

Explanation:

Given data

  • Initial concentration (C₁): 12 M
  • Initial volume (V₁): ?
  • Final concentration (C₂): 1.0 M
  • Final volume (V₂): 10.0 mL

We can calculate the initial volume of HCl using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 1.0 M × 10.0 mL / 12 M

V₁ = 0.83 mL

The required volume of the initial solution is 0.83 mL.

7 0
3 years ago
The density of liquid mercury is 13.6 g/mL. What is its density in units of ? (2.54 cm = 1 in., 2.205 lb = 1 kg)
nalin [4]

Correct question

The density of liquid mercury is 13.6 g/mL. What is its density in units of lb/in​3​? (2.5 cm = 1 in., 2.205 lbs= 1 kg., 1000 g =1 kg, 1 mL = 1 cm³)

Answer:

\rho0.4916\ lb/in^3

Explanation:

Given that;-

The density = 13.6 g/mL

Also, 1 kg = 2.205 lb

1 kg = 1000 g

So, 1000 g = 2.205 lb

1 g = 0.002205 lb

Also,

1 in = 2.54 cm

1 in³ = 16.39 cm³

1 cm³ = 1 mL

So,  1 in³ = 16.39 mL

1 mL = 0.061 in³

The expression for the calculation of density is shown below as:-

\rho=\frac{m}{V}

Thus,

\rho=\frac{13.6\ g}{1\ mL}=\frac{13.6\times 0.002205\ lb}{0.061\ in^3}=0.4916\ lb/in^3

7 0
3 years ago
Balanced equation of magnesium metal and hydrochloric acid
Setler79 [48]

The balanced chemical equation is,

2Mg+2HCl→2MgCl+H2↑

6 0
3 years ago
Jeffrey is on his skateboard and starts skating down a ramp. Ten seconds later he is travelling at
AfilCa [17]

Answer: 2m/s^2

Explanation:

Velocity of skateboard = 20.0 m/s.

Time taken = Ten seconds (10 s)

Acceleration ​= ?

Recall that acceleration is the change in velocity of a body per unit time.

i.e Acceleration = (velocity / Time)

Acceleration = 20.0m/s ➗ 10 s

Acceleration = 2m/s^2

Thus, Jeffrey acceleration was 2m/s^2

7 0
3 years ago
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