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Ivahew [28]
2 years ago
7

What is the tiny structure inside a cell

Chemistry
1 answer:
neonofarm [45]2 years ago
7 0
Nucleus............ithink
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Consider this reaction: HCO3− + H2S → H2CO3 + HS− Which is the Bronsted-Lowry base? H2S HCO3- HS– H2CO3
german

Answer:

hco3

Explanation: bc i said so

3 0
3 years ago
The elements from which group would be most likely to react
timofeeve [1]

Answer:

Group 15

That is answer c

6 0
2 years ago
Read 2 more answers
In Millikan’s experiment, the oil droplets acquire one or more negative charges by combining with the negative charges that are
zimovet [89]

Answer:

-6.4x10⁻¹⁹ C

Explanation:

The elementary charge of one electron is -1.60x10⁻¹⁹C, so each electron has its charge, and a sample with more than one electrons will have a multiple of its charge, which is proportional to the number of electrons. So, if the oil droplet had 4 electrons, thus the charge will be four times the elementary charge:

4*(-1.60x10⁻¹⁹) C = -6.4x10⁻¹⁹ C

4 0
3 years ago
student has calibrated his/her calorimeter and finds the heat capacity to be 14.2 J/°C. S/he then determines the molar heat capa
nika2105 [10]

Answer:

24.03 J/mol.ºC

Explanation:

For a calorimeter, the heat lost must be equal to the heat gained from water plus the heat gained from calorimeter, which has the same initial temperature as the water.

-Qal = Qw + Qc (minus signal represents that the heat is lost)

-mal*Cal*ΔTal = mw*Cw*ΔTw + Cc*ΔTc

Where m is the mass, C is the specific heat, ΔT is the temperature variation, al is from aluminum. w from water and c from the calorimeter. Cw = 4.186 J/gºC

-25.5*Cal*(22.7 - 100) = 99.0*4.186*(22.7 - 18.6) + 14.2*(22.7 - 18.6)

1971.15Cal = 1699.10 + 58.22

1971.15Cal = 1757.32

Cal = 0.89 J/g.ºC

The molar mass of Al is 27 g/mol

Cal = 0.89 J/g.ºC * 27 g/mol

Cal = 24.03 J/mol.ºC

6 0
3 years ago
Given the equation 2mg(s) + o2(g) → 2mgo(s) + 72.3 kj, how much heat is involved in the production of 5.0 mol of mgo? question 2
Rudik [331]
The heat is involved   in the  production of 5.0 mol of MgO  is   180 Kj

               calculation

2 Mg (s)   +O2 → 2 MgO

From  the  equation  above two  moles    of MgO  is used  therefore   

72.3   is for   2   moles

that is   72.3  kj =  2moles
                  ?      = 5  moles 

by  cross  multiplication

= 72.3  kj × 5/2     = 180  Kj  
    

7 0
2 years ago
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