What is the molecular formula of a compound if its empirical formula is CFBrO and its molar mass is 381.01 g/mol?

2 answers:

Kitty [74]2 years ago

8 0

C3F3Br3O3 should be it. Correct me if I'm wrong

4 0

A(C)+A(F)+A(Br)+A(O)=12.01+19.00+79.90+16.00=126.91

n=381.01/126.91= 3

C₃F₃Br₃O₃

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