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ladessa [460]
3 years ago
5

What is the molecular formula of a compound if its empirical formula is CFBrO and its molar mass is 381.01 g/mol?

Chemistry
2 answers:
Kitty [74]3 years ago
8 0
C3F3Br3O3 should be it. Correct me if I'm wrong
Katarina [22]3 years ago
4 0
A(C)+A(F)+A(Br)+A(O)=12.01+19.00+79.90+16.00=126.91

n=381.01/126.91= 3

C₃F₃Br₃O₃
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Hi, someone knows how to balance the following equation, and if you can thank you if you can explain how that is done:
kari74 [83]
To begin with, the equation given is not correct.
Correct equation is : CaCO3 + HCl ---> CaCl2 + H2O + CO2
It's CaCl2 not CaCl because Ca has a valency of 2 

    LHS                          RHS
CaCO3 + HCl ---> CaCl2 + H2O + CO2
First of all, to balance the equation you must look at the number of atoms on each side of the equation. 
we have 2 H on the RHS and 1 H on the LHS. So, we put a 2 on the LHS

CaCO3 + 2HCl ---> CaCl2 + H2O + CO2
Check for the LHS: 1 Ca, 1 C, 3 O, 2 H & 2 Cl on the LHS
Now check for the RHS: 1 Ca, 2 Cl, 2 H, 1 C & 3 O

Hope it helped!
7 0
3 years ago
How to economically produce fine greens
nika2105 [10]

Answer:

A transition to renewable energy and to replace fossil fuels would take care of economically producing fine greens. Also, a transition to energy conservation and efficient energy use would help in this process.

Have a great day!

5 0
3 years ago
Helppp meee Please
Fynjy0 [20]

Answer:

what do you need help with?

Explanation:

5 0
3 years ago
4.00 moles of CU(CN)2<br><br>Find the number of grams ​
UNO [17]

Hey there!

Cu(CN)₂

Find the molar mass.

Cu: 1 x 63.546 = 63.546

C: 2 x 12.01 = 24.02

N: 2 x 14.07 = 28.14

-----------------------------------

                      115.706 grams

The mass of one mole of Cu(CN)₂ is 115.706 grams.

We have 4 moles.

115.706 x 4 = 463

4.00 moles of Cu(CN)₂ has a mass of 463 grams.

Hope this helps!

6 0
3 years ago
What is the maximum number of moles of N-acetyl-p-toluidine can be prepared from 70. milliliters of 0.167 M p-toluidine hydrochl
Kitty [74]

Answer:

\large \boxed{\text{0.012 mol}}  

Explanation:

We will need a balanced equation with moles, so let's gather all the information in one place.

               CH₃C₆H₄NH₂·HCl + (CH₃CO)₂O ⟶ CH₃C₆H₄NHCOCH₃ + junk

V/mL:                    70.

c/mol·L⁻¹:             0.167

For simplicity in writing , let's call p-toluidine hydrochloride A and N-acetyl-<em>p</em>-toluidine B.

The equation is then

A + Ac₂O ⟶ B + junk

1. Moles of A

\text{Moles of A} = \text{70. mL A}\times \dfrac{\text{0.167 mmol A}}{\text{1 mL A}}= \text{12 mmol A}

2. Moles of B

The molar ratio is 1 mol B:1 mol A

Moles of B = moles of A = 12 mmol = 0.012 mol

\text{You can prepare $\large \boxed{\textbf{0.012 mol}}$ of N-acetyl-p-toluidine. }

3 0
3 years ago
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