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Arlecino [84]
2 years ago
5

Đốt cháy hết 9g kim loại magie Mg trong không khí tích tụ được 15g hợp chất magie oxit MgO. Biết rằng magie cháy là xảy ra phản

ứng với khí O2 trong không khí
a, Viết công thức về khối lượng của phán ứng xảy ra
Tính khối lượng của khí oxi phản ứng
Chemistry
1 answer:
vfiekz [6]2 years ago
5 0

Answer:

jijji[ojooooooooooooooooooooooooo

Explanation:

kjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj

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120 grams of Carbon-14 decays to 15 grams in 17,190 years.
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Mass in mg<br> salt<br> sugar<br> chalk<br> sand<br> water
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Its 470mg k dude or dudette
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Which of the following can serve as evidence to support the claim that human consumption of water impacts earths system
Brilliant_brown [7]

Ouestion: Which of the following can serve as evidence to support the claim that human consumption of water impacts earths system?

Answer & Explanation: Typically as human populations and per-capita consumption of natural resources increase, so do the negative impacts on Earth unless the activities and technologies involved are engineered otherwise. (MS-ESS3-3), (MS-ESS3-4)

Hope this helps and comment down below if you need more information!

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7 0
3 years ago
HURRY WHICH ONE IS IT??
aliya0001 [1]

Answer:

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8 0
3 years ago
Read 2 more answers
Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm
8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

\frac{dV}{dt}=10\frac{cm^3}{s}

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

\frac{dh}{dt} = ?*\frac{dV}{dt}

Of course, ?=\frac{dh}{dV}.

Now, since the volume of a cone is V=\pi r^2h/3 and the ratio r/h=15/20=3/4 or r=3/4h, the volume becomes:

V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3

We proceed to its differentiation:

\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}

Then, we compute \frac{dh}{dt}

\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}

Finally, at h=2:

\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}

Best regards.

4 0
3 years ago
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