Answer:
0.197 M
Explanation:
The reaction equation is:
H2SO4(aq) +2KOH(aq) ----> K2SO4(aq) + 2H2O(l)
number of moles of H2SO4 = 0.25 L * 0.45 M = 0.1125 moles
number of moles of KOH = 0.2 L * 0.24 M = 0.048 moles
since H2SO4 is the reactant in excess;
2 moles of KOH reacts with 1 mole of H2SO4
0.048 moles of KOH reacts with 0.048 * 1/2 = 0.024 moles of H2SO4
Amount of excess H2SO4 left unreacted = 0.1125 - 0.024 = 0.0885 moles
Total volume = 0.25 L+ 0.2 L = 0.45 L
concentration of H2SO4 = 0.0885/0.45 = 0.197 M
Approximitly 0.013787375 moles
Answer:
Explanation:
<u>1) Chemical equation (given)</u>
<u>2) Theoretical yield</u>
<u>a) Convert mass of NaHCO₃ to moles:</u>
- n = mass in grams / molar mass
- molar mass = 84.007 g/mol
- n = 2.36 g / 84.007 g/mol = 0.02809 mol
<u>b) Mole ratio:</u>
- 2 mol NaHCO₃ : 1 mol H₂CO₃
<u>c) Proportionality:</u>
- 2 mol NaHCO₃ / mol H₂CO₃ = 0.02809 mol NaHCO₃ / x
⇒ x = 0.2809 / 2 mol H₂CO₃ = 0.01405 mol H₂CO₃
<u>3) Actual yield</u>
<u>a) Mass balance</u>: 2.36 g - 1.57 g = 0.79 g
<u>b) Convert 0.79 g of carbonic acid to number of moles</u>:
- n = mass in grams / molar mass
- n = 0.79 g / 62.03 g/mol = 0.01274 mol
<u>4) Percentage yield, y (%)</u>
- y (%) = actual yield / theoretical yield × 100
- y (%) = 0.1274 mol / 0.1405 mol × 100 = 90.68%
The answer must show 3 significant figures, so y(%) = 90.7%.
Answer:
For example, elephants form groups with only females and their offspring. Once the male offspring reach a certain age, they leave the group and become solitary. Which is a benefit of this type of social group structure? A:Females do not have to compete for a mate.
Answer: mechanical
Explanation:
its a big mechanicale thing
