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saul85 [17]
3 years ago
7

The radius of an atom is dependent upon which 2 things? (Two answers)

Chemistry
1 answer:
matrenka [14]3 years ago
6 0

Answer:

The correct options are;

C. The magnitude of attraction from its nucleus

D. The distance between the electrons and its nucleus

Explanation:

The atomic radius reduces, within a given period, as we move from left to right, the number of protons increases alongside the number of electrons and the while the quantum shell to which the extra electrons are added to is the same. Therefore, the radius of the atom is dependent on the magnitude of the attraction from the nucleus

Similarly, as we progress to the next period, with an extra quantum shell, the atomic radius is seen to increase.

Therefore, the atomic radius is determined by the distance between the electrons and its nucleus.

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Suppose a substance has a heat of fusion equal to 45 calg and a specific heat of 0.75
Varvara68 [4.7K]

Answer:

The substance will be in liquid state at a temperature of 97.3 °C

Note: The question is incomplete. The complete question is given below :

Suppose a substance has a heat of fusion equal to 45 cal/g and a specific heat of 0.75 cal/g°C in the liquid state. If 5.0 kcal of heat are applied to a 50 g sample of the substance at a temperature of 24°C, what will its new temperate be? What state will the sample be in? (melting point of the substance = 27°C; specific heat of the solid =0.48 cal/g°C; boiling point of the substance = 700°C)

Explanation:

1.a) Heat energy required to raise the temperature of the substance to its melting point, H = mcΔT

Mass of solid sample = 50 g; specific heat of solid = 0.75 cal/g; ΔT = 27 - 24 = 3 °C

H = 50 × 0.75 × 3 = 112.5 calories

b) Heat energy required to convert the solid to liquid at its melting point at 27°C, H = m×l, where l = 45 cal/g

H = 50 × 45 = 2250 cal

c) Total energy used so far = 112.5 cal + 2250 cal = 2362.5 calories.

Amount of energy left = 5000 - 2362.5 = 2637.5 cal

The remaining energy is used to heat the liquid

H = mcΔT

Where specific heat of the liquid, c = 0.75 cal/g/°C, H = 2637.5 cal, ΔT = temperature change

2637.5 = 50 × 0.75 x ΔT

ΔT = 2637.5 / ( 50*0.75)

ΔT = 70.3 °C

Final temperature of sample = (70.3 + 27) °C = 97.3 °C

The substance will be in liquid state at a temperature of 97.3 °C

5 0
3 years ago
This is the chemical formula for zinc bromate: . Calculate the mass percent of oxygen in zinc bromate. Round your answer to the
Paladinen [302]

Answer:

30%

Explanation:

<em>This is the chemical formula for zinc bromate: Zn(BrO₃)₂. Calculate the mass percent of oxygen in zinc bromate. Round your answer to the nearest percentage.</em>

Step 1: Determine the mass of 1 mole of Zn(BrO₃)₂

M(Zn(BrO₃)₂) = 1 × M(Zn) + 2 × M(Br) + 6 × M(O)

M(Zn(BrO₃)₂) = 1 × 65.38 g/mol + 2 × 79.90 g/mol + 6 × 16.00 g/mol

M(Zn(BrO₃)₂) = 321.18 g/mol

Step 2: Determine the mass of oxygen in 1 mole of Zn(BrO₃)₂

There are 6 moles of atoms of oxygen in 1 mole of Zn(BrO₃)₂.

6 × m(O) = 6 × 16.00 g = 96.00 g

Step 3: Calculate the mass percent of oxygen in Zn(BrO₃)₂

%O = mO/mZn(BrO₃)₂ × 100%

%O = 96.00 g/321.18 g × 100% ≈ 30%

3 0
3 years ago
Identify a chemical reagent that can be used to distinguish solid CaCl2 from CaCO3
jenyasd209 [6]
<span>The words you seek are soluble and insoluble.The chemical you want is an acid. Add an acid (acetic acid or hydrochloric acid) and the CaCO3 will fizz but CaCl2 will not</span>
3 0
2 years ago
Consider the reaction:
stich3 [128]

Answer:

\large \boxed{\text{-851.4 kJ/mol}}

Explanation:

2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s); ΔᵣH = ?

The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is

\Delta_{\text{r}}H^{\circ} = \sum \Delta_{\text{f}} H^{\circ} (\text{products}) - \sum\Delta_{\text{f}}H^{\circ} (\text{reactants})

                            2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s)

ΔfH°/kJ·mol⁻¹:         0         -824.3         -1675.7         0

\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [1(-1675.7) + 2(0)] - [2(0) - 1(-824.3)]\\& = & -1675.7 + 824.3\\& = & \textbf{-851.4 kJ/mol}\\\end{array}\\\text{The enthalpy change is } \large \boxed{\textbf{-851.4 kJ/mol}}

7 0
3 years ago
Write a procedure for "how to crack an egg" in cooking. You must have at least 3 steps. The format of your procedure is more imp
Nataly_w [17]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Here's the procedure to Crack an egg ~

Step 1 ~

  • Hold the egg in your hand and tap it on a firm surface

Step 2 ~

  • Gently pull the shells apart

Step 3 ~

  • And release the yolk in the bowl

6 0
2 years ago
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