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frutty [35]
3 years ago
8

What bond type is expected between C & H given that their electronegativity difference is 0.4?

Chemistry
1 answer:
Olenka [21]3 years ago
7 0

Answer:

Since they have an electronegativity difference of 0.4 then they will form a Covalent Bond.

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The density of copper decreases as temperature increases (as does the density of most substances). Which change occurs in a samp
azamat

Answer: Option (c) is the correct answer.

Explanation:

As we know that density the amount of mass present in per unit volume.

Mathematically,      Density = \frac{mass}{volume}

So, it means that density is inversely proportional to volume. Hence, when there will be decrease in density of a substance then there will be increase in its volume. That is, expansion of substance will take place.

Also, boiling point of copper is 2,562 degree celsius but we are heating it up to a temperature of 95 degree celsius. This means that copper will remain in liquid state at this temperature.

Thus, we can conclude that a change which occurs in a sample of copper is that copper sample will expand.

3 0
3 years ago
What are the answers to the blanks to make this equation balanced
Eddi Din [679]

1Al+6NaOH==>2Na_{3}AlO_{3}+3H_{2}


Hope this helps!

5 0
4 years ago
A solution that contains less than the amount of solute that would be dissolved at equilibrium is considered to be
kirill115 [55]

Answer:

dilute solution

A solution containing less solute than the equilibrium amount is called a dilute solution. The solvent has a limited capacity to dissolve a solute.

Explanation:

5 0
2 years ago
A 10.0-L rigid container holds 3.00 mol H2 gas at a pressure of 4.50 atm. What is the temperature of the gas?
prisoha [69]
We can approach this problem using the ideal gas law which is as follows:

PV = nRT

P = pressure
V = volume
n = number of moles
R = gas constant, 0.08206 Latm/Kmol
T = temperature

We are asked to solve for temperature and can rearrange the equation to solve for T:

PV = nRT
T = PV/nR

Now we simply plug in the data to solve for T:

T = (4.50 atm)(10.0 L)/(3.00 mol)(0.08206 Latm/Kmol)
T = 183 K

The temperature of the gas is 183 K.
3 0
3 years ago
How much water should be added to 85 mL of 0.45 M HCI to reduce the concentration to 0.20 M?
valkas [14]

Answer:

106.25 mL

Explanation:

For this, we can use

C1×V1=C2×V2

C1 = 0.45

V1 = 85

C2= 0.20

V2= ?

0.45 × 85 = 0.20 × V2

V2= (0.45 × 85)/0.20

V2=191.25mL

To find the amount of water added, subtract V1 from V2

191.25 - 85 =106.25mL

8 0
4 years ago
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