Ask question

Ask question

All categories

4 years ago

12

How is n1 in the Rydberg equation related to the quantum number n in the Bohr model?How is n1 in the Rydberg equation related to

the quantum number n in the Bohr model?

1 answer:

andre [41]4 years ago

7 0

Ansddwdccwer:

ExplanationBecause:

You might be interested in

In a constant-pressure calorimeter, 55.0 mL of 0.340 M Ba(OH), was added to 55.0 mL of 0.680 M HCI. The reaction caused the temp

Brut [27]

Answer:

Ba(OH)2 + 2 HCl → BaCl2 + 2 H2O

The reactants are present in equimolar amounts, so there is no excess or limiting reactants.

(0.0500 L) x (0.600 mol/L HCl) x (2 mol H2O / 2 mol HCl) = 0.0300 mol H2O

(4.184 J/g·°C) x (50.0 g + 50.0 g) x (25.82 - 21.73)°C = 1711.256 J

(1711.256 J) / (0.0300 mol H2O) = 57042 J/mol = 57.0 kJ/mol H2O

Explanation:

4 0

3 years ago

If a sample of 0.362 m lithium phosphate contains 0.284 g of lithium, what is the volume of the sample?

fenix001 [56]

From the periodic table:
mass of lithium = 6.941 grams
number of moles = mass / molar mass
number of moles of Li = 0.284 / 6.941 = 0.0409 moles

Molarity can be calculated using the following rule:
molarity = number of moles of solute / liters of solution
volume (in liters) = number of moles of solute / molarity
volume = 0.0409 / 0.362 = 0.1129 liters

3 0

3 years ago

Read 2 more answers

Does water added to a flask containing chlorine gas and solid sodium react in the chemical reaction to make sodium chloride

Jet001 [13]

Answer:

Explanation:

Chemically, we can have a reaction between chlorine gas and solid sodium

This reaction is actually explosive and would produce fine powder of sodium chloride

We have the reaction as follows:

$2Na_{(s)}+Cl_{2(g)}\rightarrow2NaCl_{(s)}$

Essentally, what we can deduce from here is that we do not need to add water to the flask. Except for the reason that we would want the sodium chloride solid in the solution form, there is absolutely no reason to add water to the flask as the reaction would proceed normally

5 0

1 year ago

At standard temperature and pressure. 0.500 mole of xenon gas occupies

ANEK [815]

Answer:

0.500 mole of Xe (g) occupies 11.2 L at STP.

General Formulas and Concepts:

<u>Gas Laws</u>

STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

<u>Stoichiometry</u>

Mole ratio
Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

0.500 mole Xe (g)

<u>Step 2: Convert</u>

[DA] Set up: $\displaystyle 0.500 \ \text{mole Xe} \bigg( \frac{22.4 \ \text{L Xe}}{1 \ \text{mole Xe}} \bigg)$
[DA] Evaluate: $\displaystyle 0.500 \ \text{mole Xe} \bigg( \frac{22.4 \ \text{L Xe}}{1 \ \text{mole Xe}} \bigg) = 11.2 \ \text{L Xe}$

Topic: AP Chemistry

Unit: Stoichiometry

3 0

2 years ago

How is an oxidation half-reaction written using the reduction potential chart? How is the oxidation potential voltage determined

insens350 [35]

Oxidation half reaction is written as follows when using using reduction potential chart
example when using copper it is written as follows
CU2+ +2e- --> c(s) +0.34v
oxidasation is the loos of electron hence copper oxidation potential is as follows
cu (s) --> CU2+ +2e -0.34v

7 0

3 years ago

Read 2 more answers