Hi there!
We can use the following conversions to solve:
Total mass --> amount of mols --> amount of atoms (Avogadro's number)
Begin by calculating the amount of boron trifluoride in 3.61 grams:
3.61 g * (1 mol BF₃ / 67.8 g) ≈ 0.0532 mol BF₃
Use avogadro's number to convert:
0.0532 mol * 6.02× 10²³atoms / 1 mol = 3.203 × 10²² atoms
Answer:
The volume in the first tank = 0.32
The volume in the second tank = 2.066
The final pressure of the mixture = 203.64 K pa
Explanation:
<u>First Tank </u>
Mass = 2 kg
Pressure = 550 k pa
Temperature = 25 °c = 298 K
Gas constant for nitrogen = 0.297
From the ideal gas equation
P V = m R T
550 × V = 2 × 0.297 × 298
V = 0.32
This is the volume in the first tank.
<u>Second tank</u>
Mass = 4 kg
Pressure = 150 K pa
Temperature = 25 °c = 298 K
Gas constant for oxygen = 0.26
From the ideal gas equation
P V = m R T
150 × V = 4 × 0.26 × 298
V = 2.066
This is the volume in the second tank.
This is the iso thermal mixing. i.e.
----- (1)
Put this value in equation (1)
× 2.386 = 550 × 0.32 + 150 × 2.066
= 203.64 K pa
Therefore the final pressure of the mixture = 203.64 K pa