<u>Answer:</u> The heat of hydrogenation of the reaction is coming out to be 234.2 kJ.
<u>Explanation:</u>
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as ![\Delta H](https://tex.z-dn.net/?f=%5CDelta%20H)
The equation used to calculate enthalpy change is of a reaction is:
![\Delta H_{rxn}=\sum [n\times \Delta H_{(product)}]-\sum [n\times \Delta H_{(reactant)}]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H_%7B%28product%29%7D%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H_%7B%28reactant%29%7D%5D)
For the given chemical reaction:
![C_4H_6(g)+2H_2(g)\rightarrow C_4H_{10}(g)](https://tex.z-dn.net/?f=C_4H_6%28g%29%2B2H_2%28g%29%5Crightarrow%20C_4H_%7B10%7D%28g%29)
The equation for the enthalpy change of the above reaction is:
![\Delta H_{rxn}=[(1\times \Delta H_{(C_4H_{10})})]-[(1\times \Delta H_{(C_4H_6)})+(2\times \Delta H_{(H_2)})]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B%281%5Ctimes%20%5CDelta%20H_%7B%28C_4H_%7B10%7D%29%7D%29%5D-%5B%281%5Ctimes%20%5CDelta%20H_%7B%28C_4H_6%29%7D%29%2B%282%5Ctimes%20%5CDelta%20H_%7B%28H_2%29%7D%29%5D)
We are given:
![\Delta H_{(C_4H_{10})}=-2877.6kJ/mol\\\Delta H_{(C_4H_6)}=-2540.2kJ/mol\\\Delta H_{(H_2)}=-285.8kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20H_%7B%28C_4H_%7B10%7D%29%7D%3D-2877.6kJ%2Fmol%5C%5C%5CDelta%20H_%7B%28C_4H_6%29%7D%3D-2540.2kJ%2Fmol%5C%5C%5CDelta%20H_%7B%28H_2%29%7D%3D-285.8kJ%2Fmol)
Putting values in above equation, we get:
![\Delta H_{rxn}=[(1\times (-2877.6))]-[(1\times (-2540.2))+(2\times (-285.8))]\\\\\Delta H_{rxn}=234.2J](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B%281%5Ctimes%20%28-2877.6%29%29%5D-%5B%281%5Ctimes%20%28-2540.2%29%29%2B%282%5Ctimes%20%28-285.8%29%29%5D%5C%5C%5C%5C%5CDelta%20H_%7Brxn%7D%3D234.2J)
Hence, the heat of hydrogenation of the reaction is coming out to be 234.2 kJ.
Density is the mass of compound divided by its volume can be shown as follows:
![d = 0.5 g /mL = m /V = m /40 = 0.5](https://tex.z-dn.net/?f=d%20%3D%200.5%20g%20%2FmL%20%3D%20m%20%2FV%20%3D%20m%20%2F40%20%3D%200.5)
![m = 20 g](https://tex.z-dn.net/?f=m%20%3D%2020%20g)
40 mL of snow having 20 g of mass calculated from density.
Now, 10 cm of snow = 3.93 inches = 20 g
As, 10 inches of rain will produce 11 inches of ice as the volume of ice is bigger than rain water.
10 inches rain = 11 inches snow
3.93 inches of snow produced by
![= (3.93 * 10) /11 = 3.57 inches rain.](https://tex.z-dn.net/?f=%3D%20%283.93%20%2A%2010%29%20%2F11%20%3D%203.57%20inches%20rain.)
Thus, 3.57 incehs of rain produces by 10 cm snow.
Ionic bonding is a type of chemical bonding that involves the electrostatic attraction between oppositely charged ions, or between two atoms with sharply different electronegativities, and is the primary interaction occurring in ionic compounds
Cooper is the substance that can't be decomposed by a chemical chAnge. So 4)