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2 years ago

1. When a mechanical wave, such as sound, reflects off a surface, what can the

Chemistry

1 answer:

oksano4ka [1.4K]2 years ago

4 0

That the surface is very shiny

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What is true if a liquid and a gas are in equilibrium?

MAXImum [283]

Answer:

A - Liquid molecules forming a gas and gas molecules forming a

liquid are equal in number.

Explanation:

A P E X

6 0

2 years ago

You are instructed to create 900. mL of a 0.29 M phosphate buffer with a pH of 7.8. You have phosphoric acid and the sodium salt

Aleksandr [31]

Answer:

B and C

Explanation:

When we have to do a buffer solution we always have to choose the reaction that has the pKa closer to the desired pH value. When we find the pKa values we will obtain:

$pKa_1=-Log[6.9x10^-^3]=2.16$

$pKa_2=-Log[6.2x10^-^8]=7.20$

$pKa_3=-Log[4.8x10^-^13]=12.31$

The closer value is pKa2 with a value of 7.2. Therefore we have to use the second reaction. In which $H_2PO_4^-^1$ is the acid and $HPO_4^-^2$ is the base. Therefore the answer for the first question is B and the answer for the second question is C.

8 0

2 years ago

What does saturated mean in science?

Sergeu [11.5K]

A saturated is one in which the atoms are linked by single bonds. :)

5 0

2 years ago

Read 2 more answers

How many grams of h20 are produced if 75g of CO2 are produced. (Work Shown with the answer would be preferred.)

Agata [3.3K]

2:7 ratio of ethane to O2 = 15:x 9solve for x)
x=52.5 mol O2

5 0

2 years ago

How much heat is required to vaporize 31.5 gg of acetone (C3H6O)(C3H6O) at 25 ∘C∘C? The heat of vaporization for acetone at this

KiRa [710]

Answer:

≅ 16.81 kJ

Explanation:

Given that;

mass of acetone = 31.5 g

molar mass of acetone = 58.08 g/mol

heat of vaporization for acetone = 31.0 kJ/molkJ/mol.

Number of moles = $\frac{mass}{molar mass}$

Number of moles of acetone = $\frac{31.5}{58.08}$

Number of moles of acetone = 0.5424 mole

The heat required to vaporize 31.5 g of acetone can be determined by multiplying the number of moles of acetone with the heat of vaporization of acetone;

Hence;

The heat required to vaporize 31.5 g of acetone = 0.5424 mole × 31.0 kJ/mol

The heat required to vaporize 31.5 g of acetone = 16.8144 kJ

≅ 16.81 kJ

4 0

3 years ago