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In a photoelectric effect experiment you illuminate a metal with light of an unknown wavelength and measure the maximum kinetic

grigory [225]

Answer:

(a). The first wavelength is 401.0 nm.

(b). The metal's work function is 2.55 eV.

Explanation:

Given that,

Maximum kinetic energy = 0.65 eV

Second wavelength $\lambda_{2}= \dfrac{2}{3}\times\lambda_{1}$

(a). We need to calculate the wavelength

Using equation of work function for first wavelength

$\dfrac{hc}{\lambda_{1}}-W_{0}=0.65\ eV$ .....(I)

For second wavelength,

$\dfrac{hc}{\lambda_{2}}-W_{0}=2.3\ eV$

Put the value of second wavelength

$\dfrac{1.5 hc}{\lambda_{1}}-W_{0}=2.3\ eV$ ....(II)

By subtraction equation (I) from (II)

$0.5\dfrac{hc}{\lambda_{1}}=1.55$

$\lambda_{1}=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{3.1\times1.6\times10^{-19}}$

$\lambda_{1}=4.010\times10^{-7}\ m$

$\lambda_{1}=401.0\times10^{-9}\ m$

$\lambda_{1}=401.0\ nm$

(b). We need to calculate the work function

Using formula of work function

$W_{0}=(\dfrac{hc}{\lambda}-0.55)$

Put the value into the formula

$W_{0}=(\dfrac{6.63\times10^{-34}\times3\times10^{8}}{1.6\times10^{-19}\times401.0\times10^{-9}}-0.55)$

$W_{0}=2.55\ eV$

Hence, (a). The first wavelength is 401.0 nm.

(b). The metal's work function is 2.55 eV.

4 0

3 years ago

Read 2 more answers

How to find density of a gas.

antoniya [11.8K]

Answer:

Subtract the mass of the cylinder from the mass of the cylinder when it contains gasoline. This is the mass of the gasoline. Divide this figure by the volume, 100 ml, to get the density.

3 0

3 years ago

An autographed baseball rolls off of a 0.76 m high desk and strikes the floor 0.61 m away from the desk. how fast was it rolling

zmey [24]

d = distance = 0.76 m <span>
<span>a = acceleration due to gravity = 9.81 m/s^2</span>
u = initial velocity = 0 (as the ball rolls off the table the vertical velocity = 0
t = time = missing so we need to solve it

So we use the equation d = ut + 1/2 at², and ever since u is zero, ut is zero and the equation becomes to d = 1/2 at² and this reorders to t = sqrt (2d/a) = 0.39 seconds.

Since there are no forces performing in the horizontal direction, this means that there is no acceleration in the horizontal direction and consequently the horizontal velocity is persistent. </span>

Velocity = distance/ time.

Horizontal velocity is therefore horizontal distance/time = 0.61 m/0.39s = 1.56 m/s.

8 0

4 years ago

A go cart with a mass of 60 kg is moving at a rate of 10 m/s. How much Kinetic Energy does the go cart have?

maria [59]

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

$k = \frac{1}{2} m {v}^{2} \\$

m is the mass in kg

v is the velocity in m/s

From the question

m = 60 kg

v = 10 m/s

We have

$k = \frac{1}{2} \times 60 \times {10}^{2} \\ = 30 \times 100 \\ = 3000$

We have the final answer as

Hope this helps you

6 0

3 years ago

Read 2 more answers

Derive an expression for the acceleration of the car. Express your answer in terms of D and vt Determine the time at which the s

Bezzdna [24]

Answer:

V(car) = V(truck) at t = Dt/2

acceleration = v(car) = D/t^2

Explanation:

acceleration = v(car) = D/t^2

Since the average velocities must be the same, the car's final velocity must be twice the trunk velocity assuming the car start with zero velocity, since acceleration remain the same throughout the journey velocities at half-time point must be equal.

3 0

4 years ago