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3 years ago

Any units will do. For example, let's use the unit of "dozens":

Chemistry

1 answer:

inysia [295]3 years ago

8 0

Answer:

2 dozen of H₂ particles + 1 dozen of O₂ particles → 2 dozen of H₂O particles.

Explanation:

For the reaction of water formation:

2H₂ + O₂ → 2H₂O.

It should apply the the law of conservation of mass that the no. of reactants atoms is equal to the no. of products atoms.

So, every 2.0 moles of H₂ react with 1.0 mole of O₂ to produce 2.0 moles of H₂O.

So, the represented reaction of the problem is:

2 dozen of H₂ particles + 1 dozen of O₂ particles → 2 dozen of H₂O particles.

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What are the 6 branches of chemistry and what do they study?

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Hi there!

The 6 branches of chemistry are Organic Chemistry, Inorganic Chemistry, Analytical Chemistry, Physical Chemistry, Biochemistry, and Nuclear Chemistry.

Organic Chemistry: The branch of chemistry dedicated to carbon compounds and substances.

Inorganic Chemistry: The branch of chemistry dedicated to non-carbon compounds and substances.

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4 0

4 years ago

Read 2 more answers

What is the reaction for CL^2 + 2 KBr —> 2 KCL+Br^2 of 11 grams of potassium bromide?

mylen [45]

Answer:

All the amounts of reactants and products are:

KBr

11.0g (given)

0.0924 mol

Cl₂

0.0462 mol

3.28g

KCl

0.0924 mol

6.89 g

Br₂

0.0462 mol

7.39 g

Explanation:

1. Balanced chemical equation (given)

$Cl_2+2KBr\rightarrow 2KCl+Br_2$

2. Mole ratios

$\dfrac{1molCl_2}{2molKBr}$

$\dfrac{2molKCl}{2molKBr}$

$\dfrac{1molBr_2}{2molKBr}$

3. Molar masses

Molar mass Cl₂: 70.906g/mol

Molar mass KBr: 119.002 g/mol

Molar mass KCl: 74.5513 g/mol

Molar mass KBr: 159.808 g/mol

4. Convert 11 grams of potassium bromide to moles:

#moles = mass in grams / molar mass

#mol KBr = 11g / 119.002g/mol = 0.092435mol KBr

5. Use the mole ratios to find the amounts of Cl₂, KCl, and Br₂

a) Cl₂

$\dfrac{1molCl_2}{2molKBr}\times 0.092435molKBr=0.0462molCl_2$

$0.0462175molCl_2\times 70.906g/molCl_2=3.28gCl_2$

b) KCl

$\dfrac{2molKCl}{2molKBr}\times0.092435molKBr=0.0924molKCl$

$0.092435molKCl\times 74.5513g/molKCl=6.89gKCl$

c) Br₂

$\dfrac{1molBr_2}{2molKBr}\times 0.092435molKBr=0.0462molBr_2$

$0.0462175molBr_2\times 159.808g/molBr_2=7.39gBr2$

The final calculations are rounded to 3 sginificant figures.

3 0

4 years ago

How many magnesiums are in 2mg2 O3

Doss [256]

There are two magnesium molecules or 4 atoms

7 0

3 years ago

Giving max amount of points, I just need this answered. It's a K12 assignment. Using the room temperature line (orange line) and

slamgirl [31]

Answer:

H-1 solid Ne-10 Liquid

He-2 Solid Na-11 Liquid

Li-3 Liquid to Gas Mg-12 Gas

Be-4 Gas Al-13 Gas

B-5 Gas Si-14 Gas

C-6 Gas P-15 Liquid to Gas

N-7 Liquid S-16 Liquid to Gas

O-8 Liquid CI-17 Liquid

F-9 Liquid Ar-18 Liquid

>>>>>>>>>>>>>> K-19 Gas

Ca-20 Gas

8 0

3 years ago

Part B Now that we have put a coefficient of 3 in front of CaSO4, what coefficient should go in front of CaCl2 to balance calciu

Jet001 [13]

Answer: The coefficient must be 3.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

$CaSO_4+AlCl_3\rightarrow CaCl_2+Al_2(SO_4)_3$

The number of atoms of each element has to be same on both sides, thus the balanced chemical reaction will be:

$3CaSO_4+2AlCl_3\rightarrow 3CaCl_2+Al_2(SO_4)_3$

Thus a coefficient of 3 should go in front of $CaCl_2$ to balance calcium (Ca).

4 0

3 years ago