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lara31 [8.8K]
2 years ago
5

1) What is the time a projectile object is in flight (in the air) if it is launched at a velocity of 15

Chemistry
1 answer:
tensa zangetsu [6.8K]2 years ago
7 0

Answer:

So the degree angle will be horizontally

Explanation:

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Hc1 is the formula for .
PIT_PIT [208]

Answer:

HCl is the formula for Hydrochloric acid

Explanation:

  • Chemical formula is a formula of a compound showing the symbols of elements present in the compound.
  • Chemical formula also shows the number of atoms of each element present in a compound.
  • HCl is the chemical formula of hydrochloric acid. From this formula we can tell that hydrochloric acid is made up of hydrogen and chlorine elements.
  • The formula also shows that HCl contains 1 hydrogen atom and 1 chlorine atom.
5 0
3 years ago
HELP ME PLEASE !!!!!!!!!!!
xenn [34]

Answer:

1231

Explanation:

nnfjjkdnsggjnSVDDK and that how u get the answer i a grammer

6 0
3 years ago
A catalyst decreases the activation energy of a particular exothermic reaction by 34 kJ/mol, to 57 kJ/mol. Assuming that the mec
vagabundo [1.1K]

Answer:

the activation energy for the uncatalyzed reverse reaction is 83kJ/mol

Explanation:

see the attached file

4 0
3 years ago
Which solution has the same boiling point as 0.25 mol CaCl2 dissolved in 1000 g water?
Rufina [12.5K]
The boiling point of water at 1 atm is 100 degrees celsius. However, when water is added with another substance the boiling point of it rises than when it is still a pure solvent. This called boiling point elevation, a colligative property. The equation for the boiling point elevation is expressed as the product of the ebullioscopic constant (0.52 degrees celsius / m) for water), the vant hoff factor and the concentration of solute (in terms of molality). 

 ΔT(CaCl2) = i x K x m = 3 x 0.52 x 0.25 = 0.39 °C
<span> ΔT(Sucrose) = 1 x 0.52 x 0.75 = 0.39 </span>°C<span>
</span><span> ΔT(Ethylene glycol) = 1 x 0.52 x 1 = 0.52 </span>°C<span>
</span><span> ΔT(CaCl2) = 3 x 0.52 x 0.50 = 0.78 </span>°C<span>
</span><span> ΔT(NaCl) = 2 x 0.52 x 0.25 = 0.26 </span>°C<span>
</span>
Thus, from the calculated values, we see that 0.75 mol sucrose dissolved on 1 kg water has the same boiling point with 0.25 mol CaCl2 dissolved in 1 kg water.

5 0
3 years ago
There are several ways to express solution concentration: dilute, concentrated, ppm, molarity, molality, normality. All of these
Hoochie [10]

Answer:

just pick b

Explanation:

8 0
3 years ago
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