Answer:
C6H12 (g) + 9 O2 (g) → 6 CO2 (g) + 6 H2O (l)
Explanation:
1.17×6×1023
Wich equals 7.02×1023
Your final answer is 7.02×1023
4157 J work is done by the gas , If 2 moles of helium undergo a temperature increase of 100 K at constant pressure.
<h3>What are Noble Gases ?</h3>
The noble gases are helium, argon, krypton, xenon, and radon, in order of their mass.
They are called noble gases because they are so majestic that they do not react with anything in general.
The work done can be calculated by the formula
Q=n Cp ΔT
Cp= ( 1+ f/2)R
R= 8.3144598 J. mol-1.
Cp = (1+3/2) * 8.314
Cp = 5*8.314/2
Q= 2 * 5 *8.314 *100/2
Q = 4157 J
Therefore 4157 J work is done by the gas , If 2 moles of helium undergo a temperature increase of 100 K at constant pressure.
To know more about Noble Gas
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I. The solubility of NaCl at 25 degrees C would be between the solubilities at 20 and 30 degrees C. A reasonable answer would be 36 grams/100 g water
ii. From the table, it’s clear that the salts are more soluble at higher temperatures, indicating that an increase in temperature increases solubility.
iii. At 50 degrees C, a saturated ammonium chloride solution will have 50.6 grams of salt per 100 g water. At 20 degrees C, the solution can hold only 37.3 grams of salt per 100 g water. Thus, 13.3 grams of salt will precipitate per 100 grams of water.
